Probability: Diagram-Based Questions (7)

easy 2 min read

Question

In a Venn diagram, set AA contains 60 elements, set BB contains 50 elements, and their intersection contains 20 elements. The total sample space has 100 elements. A point is chosen at random. Find: (i) P(A)P(A), (ii) P(B)P(B), (iii) P(AB)P(A \cup B), (iv) P(ABc)P(A \cap B^c), (v) P(AcBc)P(A^c \cap B^c).

Solution — Step by Step

A=60|A| = 60, B=50|B| = 50, AB=20|A \cap B| = 20, total =100= 100.

P(A)=60/100=0.6,P(B)=50/100=0.5P(A) = 60/100 = 0.6, \quad P(B) = 50/100 = 0.5 P(AB)=P(A)+P(B)P(AB)=0.6+0.50.2=0.9P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.6 + 0.5 - 0.2 = 0.9 P(ABc)=P(A)P(AB)=0.60.2=0.4P(A \cap B^c) = P(A) - P(A \cap B) = 0.6 - 0.2 = 0.4

This is “in AA but not in BB” — the leftmost crescent of the Venn diagram.

P(AcBc)=1P(AB)=10.9=0.1P(A^c \cap B^c) = 1 - P(A \cup B) = 1 - 0.9 = 0.1

This is the region outside both circles.

Final answers: (i) 0.60.6 (ii) 0.50.5 (iii) 0.90.9 (iv) 0.40.4 (v) 0.10.1.

Why This Works

A Venn diagram partitions the sample space into four mutually exclusive regions: AA only, BB only, both, and neither. Each region’s probability adds to 11. Once you know any three, you know all four.

The inclusion-exclusion formula P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B) is just a restatement that you should not double-count the intersection.

Alternative Method

Build a 2×2 contingency table with rows “in AA” / “not in AA” and columns “in BB” / “not in BB”. Fill in the four cells from given totals. Read off any probability directly. This is faster for problems with three or more sets.

Students forget that P(ABc)P(A)P(B)P(A \cap B^c) \ne P(A) - P(B). The correct formula is P(A)P(AB)P(A) - P(A \cap B). Drawing the Venn diagram and shading the region prevents this error.

Want to master this topic?

Read the complete guide with more examples and exam tips.

Go to full topic guide →

Try These Next