Find Volume of a Cone with Radius 7 cm, Height 24 cm

easy CBSE NCERT Class 9 Chapter 13 3 min read

Question

Find the volume of a cone with radius 7 cm and height 24 cm. (NCERT Class 9, Chapter 13)


Solution — Step by Step

The volume of a cone is:

V=13πr2hV = \frac{1}{3}\pi r^2 h

The 13\frac{1}{3} factor is what separates cones from cylinders — a cone holds exactly one-third the volume of a cylinder with the same base and height.

From the problem:

  • Radius r=7r = 7 cm
  • Height h=24h = 24 cm

We use π=227\pi = \frac{22}{7} here since r=7r = 7 — this cancels the 7 cleanly and gives us a whole-number answer.

V=13×227×72×24V = \frac{1}{3} \times \frac{22}{7} \times 7^2 \times 24 V=13×227×49×24V = \frac{1}{3} \times \frac{22}{7} \times 49 \times 24

Cancel 77 from 227\frac{22}{7} and 4949:

V=13×22×7×24V = \frac{1}{3} \times 22 \times 7 \times 24 V=13×3696=1232 cm3V = \frac{1}{3} \times 3696 = 1232 \text{ cm}^3
V=1232 cm3V = 1232 \text{ cm}^3

Why This Works

The formula V=13πr2hV = \frac{1}{3}\pi r^2 h can be understood by comparison. A cylinder with the same base (radius rr) and same height hh has volume πr2h\pi r^2 h. A cone with the same dimensions holds exactly one-third of that — this is a provable result from integral calculus, but for now, trust the geometry.

The choice of π=227\pi = \frac{22}{7} is deliberate here, not arbitrary. When the radius is a multiple of 7, the 227\frac{22}{7} cancels beautifully. NCERT uses r=7r = 7 in this problem precisely so the arithmetic stays clean.


Alternative Method — Decimal Approximation

If the exam allows π3.14\pi \approx 3.14 (some schools specify this):

V=13×3.14×49×24V = \frac{1}{3} \times 3.14 \times 49 \times 24 V=13×3693.12=1231.04 cm3V = \frac{1}{3} \times 3693.12 = 1231.04 \text{ cm}^3

NCERT and CBSE board exams almost always say “use π=227\pi = \frac{22}{7}” unless stated otherwise. When rr is a multiple of 7, this gives exact whole-number answers — a strong signal you’re on the right track.


Common Mistake

The most common error: forgetting the 13\frac{1}{3}. Students write V=πr2hV = \pi r^2 h directly — which is the cylinder formula. This gives 36963696 cm³ instead of 12321232 cm³, exactly three times too large. If your answer is a multiple of 3 compared to the expected answer, this is why.

A second slip: squaring the height instead of the radius. The formula is r2×hr^2 \times h, not r×h2r \times h^2. Write rr and hh clearly before substituting so you don’t mix them up mid-calculation.

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