We need to go from x+x1 to x2+x21. The connection is through squaring.
The key identity: (a+b)2=a2+2ab+b2
Here, let a=x and b=x1. Then ab=x⋅x1=1.
(x+x1)2=52=25
Expanding the left side:
x2+2⋅x⋅x1+x21=25x2+2+x21=25x2+x21=25−2=23
Why This Works
This is a classic “reciprocal expression” problem. The trick is recognizing that squaring x+x1 naturally produces x2+x21 with an extra constant (+2) that we can subtract away.
The reason the middle term simplifies so cleanly is that x⋅x1=1 regardless of the value of x. This “reciprocal property” makes these problems very tractable.
Alternative Method — Numerical Verification
We can find x from x+x1=5: multiply by x to get x2−5x+1=0.
x=25±21
Take x=25+21≈25+4.58≈4.79
Then x2≈22.94 and x21≈0.044.
x2+x21≈22.94+0.044≈23 ✓
The algebraic method is far faster than computing irrational roots.
Common Mistake
The most common error: squaring x+x1 to get x2+x21 directly, forgetting the middle term +2. (a+b)2=a2+b2 — the cross term 2ab must always be included. Here, students write 52=25=x2+x21 and get 25 instead of 23.
This pattern extends: if you know x2+x21, you can find x4+x41 by squaring again: (x2+x21)2=x4+2+x41, so x4+x41=232−2=527.
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