Sound: Numerical Problems Set (5)

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Tags Sound

Question

A tuning fork of frequency 480 Hz480\text{ Hz} produces a sound that travels at 340 m/s340\text{ m/s} in air at room temperature. (a) Find the wavelength. (b) If the same fork is sounded under water (where sound travels at 1500 m/s1500\text{ m/s}), find the new wavelength. (c) An observer moves towards the stationary fork at 20 m/s20\text{ m/s} in air — find the apparent frequency.

Solution — Step by Step

We use v=fλv = f\lambda, so λ=v/f=340/4800.708 m\lambda = v/f = 340/480 \approx 0.708\text{ m}.

Frequency is fixed by the source, not the medium. So ff stays at 480 Hz480\text{ Hz}, and only vv changes.

λwater=15004803.125 m\lambda_{\text{water}} = \frac{1500}{480} \approx 3.125\text{ m}

The sound stretches out because it travels faster.

Observer moves towards a stationary source. The Doppler formula:

f=f(v+vov)=480×340+20340=480×360340508.2 Hzf' = f\left(\frac{v + v_o}{v}\right) = 480 \times \frac{340 + 20}{340} = 480 \times \frac{360}{340} \approx 508.2\text{ Hz}

λair0.708 m\lambda_{\text{air}} \approx 0.708\text{ m}, λwater3.125 m\lambda_{\text{water}} \approx 3.125\text{ m}, f508.2 Hzf' \approx 508.2\text{ Hz}.

Why This Works

The source vibrates at a fixed rate — that fixes frequency. Wavelength then adjusts to match the speed of the medium: λ=v/f\lambda = v/f. This is why sound from underwater speakers sounds odd to us when we surface.

The Doppler formula simply counts: when we walk towards the source, we cross more wavefronts per second than a stationary observer. The fraction (v+vo)/v(v + v_o)/v captures this rate-of-crossing increase.

Alternative Method

For the Doppler part, think of it physically: if the observer approaches at 20 m/s20\text{ m/s}, the relative speed of sound and observer is 360 m/s360\text{ m/s}. Number of wavefronts crossed per second = relative speed / wavelength = 360/0.708508 Hz360/0.708 \approx 508\text{ Hz}. Same answer, no formula memorisation.

Common Mistake

Many students think the frequency changes with the medium. It does not — frequency is set by the source. What changes is wavelength. The tuning fork vibrates 480 times per second whether the air, water, or steel is around it.

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