Ray Optics: Speed-Solving Techniques (2)

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Question

A convex lens of focal length 20cm20 \, \text{cm} forms a real image at 60cm60 \, \text{cm} from itself. Find the object distance and the magnification — in under 45 seconds.

Solution — Step by Step

1v1u=1f\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

For a real image on the opposite side: v=+60cmv = +60 \, \text{cm}. For a convex lens: f=+20cmf = +20 \, \text{cm}. Object on the left: uu is negative.

1601u=120\frac{1}{60} - \frac{1}{u} = \frac{1}{20}

1u=160120=1360=260=130\frac{1}{u} = \frac{1}{60} - \frac{1}{20} = \frac{1 - 3}{60} = -\frac{2}{60} = -\frac{1}{30}

So u=30cmu = -30 \, \text{cm}. Object is 30cm30 \, \text{cm} to the left of the lens.

m=v/u=60/(30)=2m = v/u = 60 / (-30) = -2

The negative sign means the image is inverted, and the magnitude 22 means the image is twice the size of the object.

Magnification: m=2m = -2.

Why This Works

The lens formula plus the magnification formula m=v/um = v/u solve nearly every “find the object/image distance” problem in JEE/NEET. Two formulas, three lines — that is the entire toolkit.

The sign convention (Cartesian: distances measured from the optical centre, leftward negative, rightward positive) keeps the algebra automatic. We never need to “decide” if the image is real or virtual — the sign of vv tells us.

45-second rule: Identify the unknown, plug in signs by Cartesian convention, solve. If vv comes out positive, image is real and on the opposite side. If negative, virtual and on the same side as the object.

Alternative Method — Newton’s Lens Formula

For problems where we know object and image distances from the focal points (not from the lens), Newton’s form xoxi=f2x_o \cdot x_i = f^2 is faster. But for standard lens problems with distances from the lens, the basic formula wins.

Common Mistake

The biggest trap is sign errors. Students often plug in u=+30u = +30 instead of u=30u = -30, getting nonsensical answers. Always assign the sign first based on which side the object/image is on.

Another classic: confusing the lens formula 1v1u=1f\frac{1}{v} - \frac{1}{u} = \frac{1}{f} with the mirror formula 1v+1u=1f\frac{1}{v} + \frac{1}{u} = \frac{1}{f}. The minus sign vs plus sign trips up half the candidates in board exams.

NEET 2024 asked an identical structure with f=15cmf = 15 \, \text{cm} and image at 45cm45 \, \text{cm} — toppers wrote the answer in 30 seconds flat. Memorise the workflow: assign signs, plug in, simplify, read off.

For the magnification follow-up, m=v/um = v/u gives both magnitude and orientation in one shot. No additional formula required.

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