Newton's Laws of Motion: Numerical Problems Set (1)

easy 2 min read

Question

A block of mass m=5 kgm = 5\text{ kg} rests on a frictionless horizontal surface. A horizontal force F=20 NF = 20\text{ N} is applied to it. Find the acceleration of the block and the distance covered in 4 seconds, starting from rest.

Solution — Step by Step

Newton’s second law gives us Fnet=maF_{\text{net}} = ma. The surface is frictionless, so the only horizontal force is the applied FF. No need to resolve anything — the geometry is one-dimensional.

a=Fm=205=4 m/s2a = \frac{F}{m} = \frac{20}{5} = 4\text{ m/s}^2

The direction of aa matches the direction of FF — that is the whole content of the second law in 1D.

Initial velocity u=0u = 0, t=4 st = 4\text{ s}. From s=ut+12at2s = ut + \tfrac{1}{2}at^2:

s=0+12(4)(4)2=32 ms = 0 + \tfrac{1}{2}(4)(4)^2 = 32\text{ m}

Acceleration =4 m/s2= 4\text{ m/s}^2, distance =32 m= 32\text{ m}.

Why This Works

Newton’s second law is a recipe: net force divided by mass gives acceleration. Once we know aa is constant (the force is constant, mass does not change), the SUVAT equations from kinematics take over.

We do not need to track the normal force or weight in a horizontal-surface problem — they cancel vertically and contribute nothing horizontally on a frictionless floor.

Alternative Method

Using work-energy theorem: work done W=FsW = F \cdot s. Final KE =12mv2= \tfrac{1}{2}mv^2, where v=u+at=16 m/sv = u + at = 16\text{ m/s}. So W=12(5)(162)=640 JW = \tfrac{1}{2}(5)(16^2) = 640\text{ J}, giving s=640/20=32 ms = 640/20 = 32\text{ m}. Same answer, longer route. We use this when force is variable, not for clean Newton’s-law setups.

Common Mistake

Students often write F=mgF = mg and try to “balance” forces vertically when the question is purely horizontal. The vertical balance (N=mgN = mg) does not enter the calculation here at all — only horizontal FF produces horizontal aa. Keep axes separate from day one.

Want to master this topic?

Read the complete guide with more examples and exam tips.

Go to full topic guide →

Try These Next