Magnetism and Magnetic Effects: Conceptual Doubts Cleared (8)

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Question

A charged particle moves through a region with both electric and magnetic fields. It travels in a straight line at constant speed. What can we say about the field configuration? And why does this happen even though both fields exert forces?

Solution — Step by Step

The Lorentz force on a charged particle is:

F=qE+qv×B\vec{F} = q\vec{E} + q\vec{v} \times \vec{B}

For the particle to move in a straight line at constant speed, the net force must be zero (Newton’s first law).

Net force zero implies:

qE=qv×Bq\vec{E} = -q\vec{v} \times \vec{B}

The electric force must exactly cancel the magnetic force at every instant.

The magnetic force qv×Bq\vec{v} \times \vec{B} is perpendicular to both v\vec{v} and B\vec{B}. So the electric force (and therefore E\vec{E}) must be in this perpendicular direction.

The standard configuration: v\vec{v}, E\vec{E}, and B\vec{B} are mutually perpendicular, with magnitudes related by:

E=vBE = vB, or equivalently v=E/Bv = E/B.

The fields must be mutually perpendicular, and the speed must satisfy v=E/Bv = E/B. This is the velocity selector configuration.

Why This Works

The magnetic force is always perpendicular to velocity, so it can never do work — it only changes direction. To cancel it, we need an equal and opposite force, also perpendicular to velocity. The electric force fits this role only if E\vec{E} is perpendicular to v\vec{v}.

This is the principle behind the velocity selector used in mass spectrometers: only particles with exactly the right speed pass through undeflected. Faster or slower particles get pushed off-axis.

Alternative Method — Energy Argument

If the particle’s speed is constant, kinetic energy is constant, so net work is zero. Magnetic force never does work. So the electric force must also not do work — meaning E\vec{E} is always perpendicular to v\vec{v}.

This rules out any component of E\vec{E} along the motion. Combined with force balance, we get the same configuration.

Velocity selector formula to memorise: v=E/Bv = E/B. If the question asks “for what speed will particles pass undeflected,” the answer is one division.

Common Mistake

Students sometimes think that “both forces cancel” means the fields are parallel or anti-parallel. Wrong — magnetic force on a charged particle moving parallel to B\vec{B} is zero, so there is nothing for the electric force to cancel.

Another trap: assuming the particle’s charge sign matters. It doesn’t — both qEq\vec{E} and qv×Bq\vec{v} \times \vec{B} flip sign together, so the balance condition E=vBE = vB is independent of charge sign.

JEE Main 2024 asked about a Bainbridge mass spectrometer where particles enter a velocity selector then a uniform magnetic field. Students who knew v=E/Bv = E/B instantly nailed the first part. The same template appears in NEET 2022 and 2023.

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