Kinematics: Real-World Scenarios (12)

hard 3 min read

Question

A car driver on a straight Mumbai expressway sees a stalled truck 9090 m ahead while moving at 2525 m/s. His reaction time is 0.60.6 s, after which he applies brakes that produce a constant deceleration of 55 m/s2^2. Does the car hit the truck? If yes, at what speed?

Solution — Step by Step

For the first 0.60.6 s, the car keeps moving at 2525 m/s with no braking. So distance covered =25×0.6=15= 25 \times 0.6 = 15 m. After this, only 9015=7590 - 15 = 75 m of road is left between the car and the truck.

We need the distance to come to rest from u=25u = 25 m/s with a=5a = -5 m/s2^2.

0=252+2(5)s    s=62510=62.5 m0 = 25^2 + 2(-5)s \implies s = \frac{625}{10} = 62.5 \text{ m}

The braking distance is 62.562.5 m, which is less than the available 7575 m. The car can stop in time.

Total stopping distance from the moment the driver spots the truck =15+62.5=77.5= 15 + 62.5 = 77.5 m. The truck is 9090 m away. The car stops with 9077.5=12.590 - 77.5 = 12.5 m to spare.

Final Answer: The car does not hit the truck. It stops 12.512.5 m short.

Why This Works

Real-world kinematics problems almost always have a “thinking time” before the action starts. During reaction time, velocity stays constant — no equations of motion needed there, just s=uts = ut. Only after braking begins do we use v2=u2+2asv^2 = u^2 + 2as.

The trap most students fall into is treating the entire 9090 m as the braking distance. That gives a wrong required deceleration and the wrong final answer. Always split the problem into “before reaction” and “after reaction” phases.

Alternative Method

We can frame it as: what is the minimum reaction time for which the car still stops in time? Stopping distance with full 0.60.6 s reaction is 77.577.5 m. If reaction time were longer than 9062.525=1.1\frac{90 - 62.5}{25} = 1.1 s, the car would crash. This kind of inverse framing is common in JEE Main.

Do not plug s=90s = 90 m directly into v2=u2+2asv^2 = u^2 + 2as to find vv. That ignores the 0.60.6 s reaction-time gap and gives a non-zero (wrong) impact speed. The reaction-time distance is part of the total — not extra.

For NEET, examiners often replace “reaction time” with “human response delay” or “perception lag”. Same physics, different vocabulary. Underline these phrases when you read the question.

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