Half-life of a radioactive substance — how much remains after 5 half-lives

easy CBSE JEE-MAIN NEET NCERT Class 12 3 min read

Question

A radioactive substance has a half-life of 20 minutes. If you start with 1000 g of the substance, how much of it remains after 5 half-lives?


Solution — Step by Step

5 half-lives have passed. Since each half-life is 20 minutes, the total time elapsed is 5×20=1005 \times 20 = 100 minutes. We don’t actually need this number for the calculation, but it’s good to keep track.

After every half-life, exactly half the remaining substance decays. So after 1 half-life, you have 12\frac{1}{2} of the original. After 2 half-lives, you have 12×12=14\frac{1}{2} \times \frac{1}{2} = \frac{1}{4} of the original. See the pattern?

After nn half-lives, the remaining amount is:

N=N0(12)nN = N_0 \left(\frac{1}{2}\right)^n

Here, N0=1000N_0 = 1000 g and n=5n = 5.

N=1000×(12)5=1000×132=100032=31.25 gN = 1000 \times \left(\frac{1}{2}\right)^5 = 1000 \times \frac{1}{32} = \frac{1000}{32} = 31.25 \text{ g}

After 5 half-lives, 31.25 g of the substance remains.


Why This Works

Radioactive decay is a purely probabilistic process. Each nucleus has a fixed probability of decaying per unit time — it has no memory of how long it’s been sitting there. This is why the fraction that decays in each half-life is always exactly 12\frac{1}{2}, regardless of how much is left.

The formula N=N0(12)nN = N_0 \left(\frac{1}{2}\right)^n captures this beautifully. Every time nn increases by 1, we multiply by another 12\frac{1}{2}. This is exponential decay — the same mathematics that governs compound interest, just in reverse.

This topic has high weightage in both NEET and CBSE Class 12 boards. The half-life formula alone fetches direct 1-mark questions in NEET almost every year.


Alternative Method

Instead of the formula, we can track it step by step in a table. This is slower but makes the concept crystal clear — and helps when the examiner asks you to show working.

Half-life No.Amount Remaining
Start (0)1000 g
After 1st500 g
After 2nd250 g
After 3rd125 g
After 4th62.5 g
After 5th31.25 g

Each row is just the previous row divided by 2. Same answer, different route.

In MCQs, if nn is a whole number, compute 2n2^n mentally and divide N0N_0 by it. 25=322^5 = 32, so the answer is 1000÷32=31.251000 \div 32 = 31.25 g. Takes under 10 seconds.


Common Mistake

Students often confuse “5 half-lives have passed” with “the substance is 50% gone” — that’s only true after 1 half-life. After 5 half-lives, only 132\frac{1}{32} ≈ 3.125% remains. The decay is exponential, not linear. Drawing the step table (shown above) for 30 seconds in the exam prevents this slip every time.

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