Fluid Mechanics: Conceptual Doubts Cleared (2)

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Question

A block of wood floats half-submerged in water. If the same block is placed in a fluid of density 0.60.6 g/cm³, will it float higher, lower, or sink? Many students answer “sink” because the new fluid is less dense than water. Why is that often wrong?

Solution — Step by Step

If the block floats half-submerged in water, half its volume is under water. By Archimedes’ principle, the buoyant force equals the weight of displaced water.

For floating equilibrium: weight of block = weight of displaced water.

ρwoodVg=ρwater(V/2)g\rho_\text{wood} \cdot V \cdot g = \rho_\text{water} \cdot (V/2) \cdot g

So ρwood=ρwater/2=0.5g/cm3\rho_\text{wood} = \rho_\text{water}/2 = 0.5 \, \text{g/cm}^3.

New fluid has ρ=0.6g/cm3\rho = 0.6 \, \text{g/cm}^3. Wood has ρwood=0.5g/cm3\rho_\text{wood} = 0.5 \, \text{g/cm}^3.

Since ρwood<ρfluid\rho_\text{wood} < \rho_\text{fluid}, the wood will float — not sink.

Let ff be the fraction submerged. Floating equilibrium gives:

ρwoodVg=ρfluid(fV)g\rho_\text{wood} \cdot V \cdot g = \rho_\text{fluid} \cdot (fV) \cdot g

f=ρwood/ρfluid=0.5/0.6=5/60.833f = \rho_\text{wood}/\rho_\text{fluid} = 0.5/0.6 = 5/6 \approx 0.833

So about 83%83\% of the block is now submerged — much more than the 50%50\% in water.

The block floats lower (more submerged) but does not sink. Submerged fraction: 5/65/6.

Why This Works

The rule for floating: a block floats if and only if its density is less than the fluid’s density. The new fluid is denser than the wood (0.6>0.50.6 > 0.5), so floating still happens — just with a larger submerged fraction.

The trap “less dense fluid → sink” is only true if the fluid becomes less dense than the wood. Here, the fluid is still denser than the wood.

Quick formula: Submerged fraction =ρobject/ρfluid= \rho_\text{object}/\rho_\text{fluid} for any floating object. We can solve any floating problem in one step once we know the densities.

Alternative Method — Force Balance Directly

Write the buoyant force Fb=ρfluidVsubmergedgF_b = \rho_\text{fluid} \cdot V_\text{submerged} \cdot g and set it equal to weight ρwoodVg\rho_\text{wood} \cdot V \cdot g. Cancel gg, divide both sides by VV, and we land on the same fraction formula.

This is the more general method — works even for objects with non-uniform density (as long as they are in equilibrium).

Common Mistake

The big mistake: assuming “less dense fluid means object sinks.” Sinking happens only when the fluid is less dense than the object — not just less dense than water.

Another classic: thinking the block floats higher in the new fluid because the fluid is “lighter.” Actually it is the opposite — a less dense fluid provides less buoyancy per unit submerged volume, so we need MORE submerged volume to support the same weight.

JEE Main 2023 had a similar problem with ice floating in water and oil. Students who confused “less dense” with “object sinks” lost 4 marks. The submerged fraction formula f=ρobj/ρfluidf = \rho_\text{obj}/\rho_\text{fluid} is one of the highest-yield formulas in fluids — memorise it.

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