Electrostatics: PYQ Walkthrough (10)

easy 2 min read

Question

Two point charges +4μC+4\,\mu\text{C} and 1μC-1\,\mu\text{C} are placed 30 cm apart on the x-axis. Find the position on the line joining them where the electric field is zero. (JEE Main 2023 PYQ pattern.)

Solution — Step by Step

Field is zero only on the line outside the smaller charge — never between two opposite charges (the fields add up there) and never beyond the larger charge (the larger field always wins). So the null point is beyond the 1μC-1\,\mu\text{C} side.

Let the null point be at distance xx from the 1μC-1\,\mu\text{C} charge, on the side away from +4μC+4\,\mu\text{C}. Then it is at distance (0.30+x)(0.30 + x) from the larger charge.

k(4μC)(0.30+x)2=k(1μC)x2\frac{k(4\,\mu\text{C})}{(0.30+x)^2} = \frac{k(1\,\mu\text{C})}{x^2}

Cross-multiply and take square roots:

20.30+x=1x    2x=0.30+x    x=0.30 m\frac{2}{0.30+x} = \frac{1}{x} \implies 2x = 0.30 + x \implies x = 0.30\text{ m}

So the null point is 30 cm from the 1μC-1\,\mu\text{C} charge, or 60 cm from the +4μC+4\,\mu\text{C} charge.

Final answer: 30 cm beyond the 1μC-1\,\mu\text{C} charge (60 cm from the positive charge)

Why This Works

Outside the negative charge, both field contributions point in opposite directions (the positive pushes outward, the negative pulls back toward itself). Equating magnitudes finds the cancellation point.

The square-root trick — q1/q2\sqrt{q_1/q_2} ratio of distances — is the fastest way to solve this family of questions. Memorise it.

Alternative Method

You could write the field expression with signs and solve E=0E = 0. Same answer but more bookkeeping with signs.

Common Mistake

Students place the null point between the two charges. Visualise the field directions first: between ++ and -, both arrows point from ++ toward -, so they add — never cancel. The null is always on the “outside” of the smaller charge.

JEE Main asks “potential = 0” and “field = 0” questions back to back. Don’t confuse them — potential can be zero between opposite charges (closer to the smaller one), but field cannot.

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