Electromagnetic Induction: Exam-Pattern Drill (4)

easy 2 min read

Question

A rectangular coil of 200200 turns and area 0.050.05 m² is placed in a uniform magnetic field of 0.40.4 T with its plane perpendicular to the field. The coil is rotated through 90°90° about an axis perpendicular to the field in 0.10.1 s. Find the average emf induced in the coil. This pattern appeared in JEE Main 2024 and CBSE board paper.

Solution — Step by Step

When the plane of the coil is perpendicular to B\vec{B}, the area vector is parallel to B\vec{B}, so θ=0°\theta = 0°.

Φ1=NBAcos0°=200×0.4×0.05×1=4 Wb\Phi_1 = NBA\cos 0° = 200 \times 0.4 \times 0.05 \times 1 = 4 \text{ Wb}

After rotating by 90°90°, the area vector is perpendicular to B\vec{B}, so θ=90°\theta = 90°.

Φ2=NBAcos90°=0 Wb\Phi_2 = NBA\cos 90° = 0 \text{ Wb}

εavg=ΔΦΔt=400.1=40 V|\varepsilon_{\text{avg}}| = \left|\frac{\Delta\Phi}{\Delta t}\right| = \frac{4 - 0}{0.1} = 40 \text{ V}

Average induced emf =40= 40 V.

Why This Works

Faraday’s law says the induced emf equals the rate of change of magnetic flux. For an N-turn coil, the flux linkage is NΦN\Phi, and:

ε=d(NΦ)dt\varepsilon = -\frac{d(N\Phi)}{dt}

For an average emf over a finite interval, just use the change in flux divided by the time interval — no calculus needed. The minus sign (Lenz’s law) tells us the direction; magnitude is what the question asks.

Alternative Method

Compute the area swept by the area vector. From θ=0\theta = 0 to θ=90°\theta = 90°, the projected area changes by AA fully. So ΔΦ=NBA=4\Delta\Phi = NBA = 4 Wb in the rotation. Same result.

Students confuse “plane perpendicular to field” with “plane parallel to field”. When the plane is perpendicular to B\vec{B}, the area vector is parallel to B\vec{B}, giving maximum flux. Always sketch the orientation.

For a rotating coil, instantaneous emf is ε=NBAωsin(ωt)\varepsilon = NBA\omega \sin(\omega t), and average emf over a quarter cycle is 2NBAωπ\dfrac{2NBA\omega}{\pi}. Here we used the simpler ΔΦ/Δt\Delta\Phi/\Delta t form because the question asks for average, not peak.

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