Question
Draw and explain the current-voltage (I-V) characteristics of a PN junction diode for both forward and reverse bias.
Solution — Step by Step
A PN junction diode is formed when a P-type semiconductor (with holes as majority carriers) is joined to an N-type semiconductor (with electrons as majority carriers). At the junction, a depletion region forms where positive and negative ions create an internal electric field (potential barrier of ~0.3 V for germanium, ~0.7 V for silicon).
When the positive terminal of the battery is connected to the P-side and negative to the N-side:
What happens: The external voltage opposes the internal potential barrier. As the applied voltage approaches the threshold voltage ( ≈ 0.7 V for Si, 0.3 V for Ge), the barrier is overcome. Current begins to flow exponentially.
I-V characteristic (forward bias):
- For : Very small current (essentially zero — barrier not overcome)
- At : Current begins to rise sharply
- For : Current rises steeply (exponentially) with small increase in voltage
- The I-V curve is non-linear — the diode doesn’t obey Ohm’s law
The diode acts like a closed switch above threshold — it conducts heavily.
Equation: where is the reverse saturation current and is the ideality factor.
When the negative terminal is connected to the P-side and positive to the N-side:
What happens: The external voltage adds to the internal barrier, widening the depletion region. Majority carriers cannot cross. Only minority carriers (few thermally generated electrons in P-type, holes in N-type) cross, giving a very small reverse saturation current (order of µA or nA).
I-V characteristic (reverse bias):
- Current is almost constant (very small) regardless of increasing reverse voltage — this is
- At very high reverse voltage, the junction breaks down — either:
- Zener breakdown (heavily doped, low voltage): occurs at a specific Zener voltage
- Avalanche breakdown (lightly doped, high voltage): impact ionisation
At breakdown, current increases sharply. The Zener diode is specially designed to operate in this region for voltage regulation.
The diode acts like an open switch in reverse bias (before breakdown).
The complete I-V curve occupies two quadrants:
Quadrant I (forward bias): Voltage positive, current positive — rises steeply after threshold.
Quadrant III (reverse bias): Voltage negative, current negative — very small magnitude (flat at ) until breakdown at , where current suddenly increases.
Key values to label on the diagram:
- Threshold voltage (): ~0.7 V (Si), ~0.3 V (Ge)
- Reverse saturation current (): Very small, temperature dependent
- Breakdown voltage (): Typically 5–200 V depending on diode type
Why This Works
The exponential I-V relationship in forward bias comes from the Boltzmann distribution of charge carriers. At room temperature, carriers with enough thermal energy to overcome the barrier are exponentially more common as the barrier height decreases (which is what forward bias does).
The flat reverse saturation current is due to minority carriers — very few are thermally generated, and once they reach the junction, they get swept across by the internal field. More reverse voltage can’t create more minority carriers (they’re thermally generated, not voltage-generated).
Common Mistake
Students often draw the forward bias curve as starting from zero and rising linearly. The curve is not linear — it rises very slowly (near zero) until threshold, then rises sharply (exponentially). The knee of the curve at threshold voltage is a critical feature. Also, many students draw breakdown in reverse bias as a straight vertical line — it should be drawn as a sharp steep curve (nearly vertical but not perfectly so).
For CBSE Class 12 board exams, draw the curve in two parts — forward and reverse — on the same axes. Label V on the x-axis (positive to the right, negative to the left) and I on the y-axis. Mark , , and clearly with arrows. This diagram, drawn neatly with labels, typically earns full 3 marks.