NEET Weightage:

NEET Chem — Chemical Equilibrium Deep Dive

NEET Chem — Chemical Equilibrium Deep Dive — NEET strategy, weightage, PYQs, traps

4 min read

Chapter Overview & Weightage

Chemical Equilibrium is a perennial favourite for NEET. Direct questions appear every year, plus the concepts power Ionic Equilibrium and Electrochemistry. Total contribution: 8-12 marks across the paper.

YearDirect QsMarks
2024312
202328
2022312
202128
202028

NEET Chemistry is heavily mark-weighted toward chapters with direct numerical or conceptual MCQs. Equilibrium fits the bill perfectly.

Key Concepts You Must Know

  • Reversible reactions: forward and reverse rates equal at equilibrium.
  • Equilibrium constant: KcK_c (in concentrations), KpK_p (in partial pressures).
  • Relation: Kp=Kc(RT)ΔngK_p = K_c (RT)^{\Delta n_g}.
  • Le Chatelier’s principle: equilibrium shifts to minimise applied stress.
  • Effects of concentration, pressure, temperature, catalysts on equilibrium.
  • Reaction quotient QQ: predicts direction of shift.
  • Coupled reactions: ΔG\Delta G adds, KK multiplies.
  • Heterogeneous equilibria: pure solids and liquids excluded from KK.

Important Formulas

For reaction aA+bBcC+dDa A + b B \rightleftharpoons c C + d D:

Kc=[C]c[D]d[A]a[B]bK_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}

Kp=Kc(RT)ΔngK_p = K_c (RT)^{\Delta n_g} where Δng=(c+d)(a+b)\Delta n_g = (c + d) - (a + b) (gaseous moles only).

ΔG°=RTlnK\Delta G° = -RT \ln K

ΔG°<0K>1\Delta G° < 0 \Rightarrow K > 1 (forward favoured). ΔG°>0K<1\Delta G° > 0 \Rightarrow K < 1 (backward favoured).

StressShift
Add reactantForward
Add productBackward
Increase pressureToward fewer moles of gas
Increase TT (endo)Forward
Increase TT (exo)Backward
CatalystNo shift, but reach equilibrium faster

Solved Previous Year Questions

PYQ 1 (NEET 2024)

For N2+3H22NH3\text{N}_2 + 3\text{H}_2 \rightleftharpoons 2\text{NH}_3 at equilibrium, KpK_p at 400 K400\text{ K} is 1.6×1031.6 \times 10^{-3}. What is KcK_c?

Δng=24=2\Delta n_g = 2 - 4 = -2. Kp=Kc(RT)ΔngK_p = K_c (RT)^{\Delta n_g}, so Kc=Kp/(RT)2=Kp(RT)2K_c = K_p / (RT)^{-2} = K_p \cdot (RT)^2.

RT=0.0821×400=32.84RT = 0.0821 \times 400 = 32.84.

Kc=1.6×103×32.842=1.6×103×1078.51.726K_c = 1.6 \times 10^{-3} \times 32.84^2 = 1.6 \times 10^{-3} \times 1078.5 \approx 1.726.

PYQ 2 (NEET 2023)

Which of these favours the forward reaction in N2+O22NO\text{N}_2 + \text{O}_2 \rightleftharpoons 2\text{NO}, ΔH>0\Delta H > 0?

(a) Decrease temperature (b) Increase pressure (c) Increase temperature (d) Add a catalyst.

For endothermic, increase TT shifts forward. Δng=0\Delta n_g = 0, so pressure has no effect. Catalyst speeds equilibrium but does not shift it.

Answer: (c) Increase temperature.

PYQ 3 (NEET 2022)

At 500 K500\text{ K}, Kc=4K_c = 4 for H2+I22HI\text{H}_2 + \text{I}_2 \rightleftharpoons 2\text{HI}. If 1 mol1\text{ mol} each of H2\text{H}_2 and I2\text{I}_2 is taken in a 1 L1\text{ L} vessel, find equilibrium concentration of HI.

Let xx moles dissociate. At equilibrium: [H2]=1x[\text{H}_2] = 1-x, [I2]=1x[\text{I}_2] = 1-x, [HI]=2x[\text{HI}] = 2x.

Kc=(2x)2/(1x)2=4    2x/(1x)=2    x=1/2K_c = (2x)^2 / (1-x)^2 = 4 \implies 2x/(1-x) = 2 \implies x = 1/2 (taking positive root).

[HI]=2(1/2)=1 M[\text{HI}] = 2(1/2) = 1\text{ M}.

Difficulty Distribution

Sub-topicEasyMediumHard
Definitions70%25%5%
KcK_c vs KpK_p30%60%10%
Le Chatelier50%40%10%
ICE-table problems20%50%30%

ICE-table problems are the hardest — be comfortable with quadratic factoring.

Expert Strategy

Always set up an ICE (Initial, Change, Equilibrium) table for unknowns. The discipline alone earns 1-2 marks in NEET subjective stages and saves errors.

For Le Chatelier, write down the sign of ΔH\Delta H first. Forgetting whether the reaction is endo or exo is the most common error.

Memorise: increasing TT favours the endothermic direction; increasing pressure favours fewer moles of gas. Two rules cover most NEET MCQs.

Common Traps

Including pure solids/liquids in KK. They have constant activity (= 1) and do not appear. NEET MCQs love listing solids in the expression as a wrong option.

Using the wrong Δng\Delta n_g in Kp=Kc(RT)ΔngK_p = K_c (RT)^{\Delta n_g}. Count only gases — solids and liquids do not enter Δng\Delta n_g.

Thinking a catalyst shifts equilibrium. It does not — it just speeds up both directions equally, reaching equilibrium faster.