Time, speed, distance — relative speed, average speed, train problems

medium CBSE 3 min read

Question

A train 200 m long crosses a platform 300 m long in 25 seconds. Find the speed of the train. If another train of length 150 m approaches from the opposite direction at 72 km/h, how long will they take to cross each other?

(CBSE 7 & 8 pattern)


Solution — Step by Step

When a train crosses a platform, the total distance covered = train length + platform length.

Total distance=200+300=500 m\text{Total distance} = 200 + 300 = 500 \text{ m} Speed=50025=20 m/s=20×185=72 km/h\text{Speed} = \frac{500}{25} = 20 \text{ m/s} = 20 \times \frac{18}{5} = \mathbf{72 \text{ km/h}}

When two objects move toward each other, their relative speed = sum of speeds.

Train 1: 7272 km/h =20= 20 m/s

Train 2: 7272 km/h =20= 20 m/s

Relative speed=20+20=40 m/s\text{Relative speed} = 20 + 20 = 40 \text{ m/s}

Total distance to cross each other = sum of both train lengths:

Distance=200+150=350 m\text{Distance} = 200 + 150 = 350 \text{ m} Time=35040=8.75 s\text{Time} = \frac{350}{40} = \mathbf{8.75 \text{ s}}

Why This Works

The fundamental relationship is Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}. For crossing problems, we need to figure out the correct distance (what exactly needs to pass what) and the correct speed (actual or relative).

graph TD
    A["TSD Problem"] --> B{"What's crossing what?"}
    B -->|"Train crosses a pole/person"| C["Distance = train length"]
    B -->|"Train crosses a platform/bridge"| D["Distance = train + platform"]
    B -->|"Two trains crossing"| E["Distance = sum of lengths"]
    E --> F{"Direction?"}
    F -->|"Opposite"| G["Relative speed = v₁ + v₂"]
    F -->|"Same direction"| H["Relative speed = |v₁ - v₂|"]
    A --> I{"Average speed?"}
    I --> J["avg speed = total distance<br/>÷ total time<br/>(NOT average of speeds!)"]

Alternative Method — Unit Conversion Shortcut

To convert km/h to m/s: multiply by 5/185/18.

To convert m/s to km/h: multiply by 18/518/5.

For the train problem, you can work entirely in km/h or entirely in m/s — just be consistent.

Average speed is NOT the average of two speeds. If you travel 60 km at 30 km/h and 60 km at 60 km/h, the average speed = 1202+1=40\dfrac{120}{2 + 1} = 40 km/h, not (30+60)/2=45(30 + 60)/2 = 45 km/h. Use total distance divided by total time, always.


Common Mistake

When two trains move in the same direction, students add their speeds instead of subtracting. If both go in the same direction, the faster one approaches the slower one at a relative speed of v1v2v_1 - v_2. Adding gives the relative speed for opposite directions only. This changes the answer dramatically — getting it wrong can double or halve your time.

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