Statistics: Common Mistakes and Fixes (1)

easy 2 min read

Question

The mean of 10 numbers is 25. If one number aa is replaced by a+12a + 12, what is the new mean? If instead the same number is replaced by twice its value, find the new mean in terms of aa.

Solution — Step by Step

If mean of 10 numbers is 25, total sum is 250250.

The sum increases by 1212. New sum =262= 262. New mean:

xˉnew=262/10=26.2\bar{x}_{new} = 262/10 = 26.2

The sum increases by aa (since 2aa=a2a - a = a). New sum =250+a= 250 + a. New mean:

xˉnew=(250+a)/10=25+a/10\bar{x}_{new} = (250 + a)/10 = 25 + a/10

If a=0a = 0, mean stays at 2525 (replacing 0 with 0 is a non-change, but 2×0=02 \times 0 = 0, so no change — correct). If a=50a = 50, mean increases by 5 — replacing one number with one 5050 larger raises sum by 5050, divided by 1010 values gives +5+5 — correct.

Final answers: Case 1 mean =26.2= 26.2; Case 2 mean =25+a/10= 25 + a/10.

Why This Works

Mean is sum/count. When you replace one element, only the sum changes (count is constant). The change in sum equals (new value) − (old value). Divide that change by the count to get the change in mean.

This is faster than recomputing the sum from scratch. Useful for “what if” problems.

Alternative Method

Direct: original sum =25×10=250= 25 \times 10 = 250. Sum without aa is 250a250 - a. Add new value back. Divide by 1010. Same approach, written differently.

Students often subtract the old value once but forget to add the new one. Mean change formula: Δxˉ=(vnewvold)/n\Delta \bar{x} = (v_{new} - v_{old})/n, not vold/n+vnew/n-v_{old}/n + v_{new}/n written in two parts. Combine into one step.

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