Permutations and Combinations: Common Mistakes and Fixes (3)

hard 3 min read

Question

In how many ways can 77 persons be seated around a round table such that two specific persons AA and BB never sit next to each other?

Solution — Step by Step

For nn persons around a circular table, total arrangements =(n1)!=6!=720= (n-1)! = 6! = 720.

Treat AA and BB as a single unit. Now we have 66 “units” to arrange in a circle: 5!=1205! = 120. Within the unit, AA and BB can swap: factor of 22.

Together=5!×2=240\text{Together} = 5! \times 2 = 240
Not together=720240=480\text{Not together} = 720 - 240 = 480

Final answer: 480\mathbf{480} arrangements.

Why This Works

The complement principle is the standard PnC weapon: rather than counting “not adjacent” directly (which means choosing AA‘s seat, then carefully picking BB‘s non-neighbouring seats — easy to miscount), count the easier opposite event “adjacent” and subtract from total.

The “treat together as a unit” trick reduces an adjacency problem to a permutation of fewer items. The internal swap (here, AA-BB vs BB-AA) is a separate factor.

Alternative Method

Direct counting: fix AA‘s seat (since it’s circular, this kills the rotational symmetry — gives 6!6! for the rest, but we’re working with (n1)!(n-1)! already). Now BB has 66 remaining seats, of which 22 are adjacent to AA. So BB has 44 non-adjacent choices. The remaining 55 persons can be arranged in 5!5! ways:

Not together=4×5!=4×120=480\text{Not together} = 4 \times 5! = 4 \times 120 = 480 \checkmark

Same answer through different reasoning. Always cross-check using both methods on the day of the exam.

Common Mistake

Forgetting the internal ×2\times 2 when treating AA and BB as a unit. The unit could be "ABAB" or "BABA", and these are different arrangements. Missing this factor gives 720120=600720 - 120 = 600 — a popular wrong answer.

Using 7!7! instead of (71)!=6!(7-1)! = 6! for circular permutations. The first person’s seat doesn’t matter in a circular arrangement (all rotations look the same), so we lose one degree of freedom.

The “round table + adjacency” pattern shows up in roughly 11 JEE Main paper out of 44 in the last decade. Practise both versions: “always together” and “never together” — the second is just total minus the first.

Want to master this topic?

Read the complete guide with more examples and exam tips.

Go to full topic guide →

Try These Next