Two facts pin down an ellipse with centre at origin and axes along coordinate axes: c (focal distance) and one of a, b or the latus rectum. We had c and the latus rectum, and the fundamental identity c2=a2−b2 closed the loop.
The latus rectum formula 2b2/a comes from substituting x=c in the ellipse equation: y=±b2/a, giving full chord length 2b2/a.
Alternative Method
We could use eccentricity e=c/a. Then b2=a2(1−e2) and latus rectum =2b2/a=2a(1−e2). Two equations in two unknowns (a,e). Same answer through different algebra.
Common Mistake
The most common error is assuming a<b for an ellipse with foci on the x-axis. The major axis (and therefore a) is along whichever axis the foci lie on. If the foci are on y-axis, the form becomes b2x2+a2y2=1 with a>b and foci (0,±c).
Quick latus rectum check: for 25x2+16y2=400, divide by 400: 16x2+25y2=1. Here a2=25 (foci on y-axis), latus rectum =2(16)/5=32/5. Practise spotting which axis is major in 5 seconds.
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