JEE Weightage: 8-10%

JEE Maths — Probability And Statistics Complete Chapter Guide

Probability And Statistics for JEE. Chapter weightage, key formulas, solved PYQs, preparation strategy. Free step-by-step solutions on doubts.ai.

9 min read

Chapter Overview & Weightage

Probability and Statistics is one of the most reliable scoring chapters in JEE Main. Unlike Calculus or Algebra where you can get stuck for 10 minutes, a Probability question usually resolves in 2-3 minutes if you know your Bayes or distribution formula cold.

JEE Main consistently drops 2-3 questions from this chapter every sitting. That’s 8-12 marks — enough to shift your percentile meaningfully.

Weightage trend (JEE Main):

YearQuestionsMarksTopics Covered
2024312Bayes, Binomial, Classical
202328Conditional, Binomial
2022312Classical, Bayes, Variance
20212–38–12Binomial, Conditional
202028Classical, Bayes

Expected weightage: 8–10% of Maths section. JEE Advanced tests deeper combinatorial probability — classical counting-heavy problems.

Statistics (mean, variance, standard deviation) is lighter in JEE Main — usually 1 question, often straightforward. Don’t skip it; it’s free marks.


Key Concepts You Must Know

Prioritised by how often they appear in PYQs:

High Priority (appear almost every session)

  • Classical probability — equally likely outcomes, P(A) = favourable/total
  • Conditional probability — P(A|B) = P(A∩B)/P(B); the foundation for Bayes
  • Bayes’ Theorem — reverse conditional; given the outcome, find the cause
  • Binomial distribution — n independent trials, success probability p, find P(X = r)
  • Mean and Variance of Binomial — μ = np, σ² = npq

Medium Priority (1-2 times per year)

  • Total Probability Theorem — when sample space is partitioned into exhaustive events
  • Independent events — P(A∩B) = P(A)·P(B); must verify, not assume
  • Mutually exclusive vs exhaustive — conceptual questions and traps
  • Variance and Standard Deviation — Var(X) = E(X²) – [E(X)]²

Lower Priority but don’t skip

  • Poisson distribution — rarely in Main, appears in Advanced occasionally
  • Random variable — discrete distributions, expected value calculations
  • Geometric probability — length/area ratio problems

Important Formulas

P(A)=Number of favourable outcomesTotal number of outcomesP(A) = \frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

When to use: Sample space is finite and all outcomes are equally likely — dice, cards, balls in a bag, arrangement problems.

P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B)

For mutually exclusive events: P(AB)=P(A)+P(B)P(A \cup B) = P(A) + P(B)

When to use: “At least one of A or B” type questions.

P(AB)=P(AB)P(B),P(B)0P(A \mid B) = \frac{P(A \cap B)}{P(B)}, \quad P(B) \neq 0

When to use: Any question where an event has “already occurred” — “given that the first ball is red, find probability the second is blue.”

P(AiB)=P(Ai)P(BAi)j=1nP(Aj)P(BAj)P(A_i \mid B) = \frac{P(A_i) \cdot P(B \mid A_i)}{\displaystyle\sum_{j=1}^{n} P(A_j) \cdot P(B \mid A_j)}

When to use: You know prior probabilities (causes) and want the posterior (which cause, given the effect). Bag problems, disease testing, factory defect questions.

P(X=r)=(nr)prqnr,q=1pP(X = r) = \binom{n}{r} p^r q^{n-r}, \quad q = 1-p

Mean: μ=np\mu = np | Variance: σ2=npq\sigma^2 = npq

When to use: Fixed number of identical, independent trials with two outcomes (success/failure). “A coin is tossed 10 times, find P(exactly 4 heads).”

Var(X)=E(X2)[E(X)]2=xi2pi(xipi)2\text{Var}(X) = E(X^2) - [E(X)]^2 = \sum x_i^2 p_i - \left(\sum x_i p_i\right)^2

When to use: Given a probability distribution table, always use this form — faster than computing deviations individually.


Solved Previous Year Questions

PYQ 1 — Bayes’ Theorem (JEE Main 2024 Shift 1)

Question: Bag I has 3 red and 4 black balls. Bag II has 5 red and 6 black balls. One bag is selected at random and a ball is drawn. If the ball is red, find the probability it came from Bag II.

Solution:

Let B1B_1 = Bag I selected, B2B_2 = Bag II selected, RR = Red ball drawn.

P(B1)=P(B2)=12P(B_1) = P(B_2) = \frac{1}{2}
P(RB1)=37,P(RB2)=511P(R \mid B_1) = \frac{3}{7}, \quad P(R \mid B_2) = \frac{5}{11} P(R)=P(B1)P(RB1)+P(B2)P(RB2)P(R) = P(B_1)\cdot P(R\mid B_1) + P(B_2)\cdot P(R\mid B_2) =1237+12511=314+522=33154+35154=68154=3477= \frac{1}{2}\cdot\frac{3}{7} + \frac{1}{2}\cdot\frac{5}{11} = \frac{3}{14} + \frac{5}{22} = \frac{33}{154} + \frac{35}{154} = \frac{68}{154} = \frac{34}{77} P(B2R)=P(B2)P(RB2)P(R)=125113477=5223477=5227734=5×72×34=3568P(B_2 \mid R) = \frac{P(B_2)\cdot P(R\mid B_2)}{P(R)} = \frac{\frac{1}{2}\cdot\frac{5}{11}}{\frac{34}{77}} = \frac{\frac{5}{22}}{\frac{34}{77}} = \frac{5}{22}\cdot\frac{77}{34} = \frac{5\times 7}{2\times 34} = \frac{35}{68}

Answer: 3568\dfrac{35}{68}


PYQ 2 — Binomial Distribution (JEE Main 2023 January Session)

Question: A fair die is thrown 5 times. Find the probability of getting an even number at least 4 times.

Solution:

Each throw: P(even) = 3/6 = 1/2 = p. So q = 1/2, n = 5.

“At least 4 times” means P(X = 4) + P(X = 5).

P(X=4)=(54)(12)4(12)1=5132=532P(X=4) = \binom{5}{4}\left(\frac{1}{2}\right)^4\left(\frac{1}{2}\right)^1 = 5 \cdot \frac{1}{32} = \frac{5}{32} P(X=5)=(55)(12)5=132P(X=5) = \binom{5}{5}\left(\frac{1}{2}\right)^5 = \frac{1}{32} P(X4)=532+132=632=316P(X \geq 4) = \frac{5}{32} + \frac{1}{32} = \frac{6}{32} = \frac{3}{16}

Answer: 316\dfrac{3}{16}


PYQ 3 — Variance (JEE Main 2022 July Session)

Question: A random variable X has the following distribution:

X0123
P(X)k2k3k4k

Find the variance of X.

k+2k+3k+4k=1    10k=1    k=110k + 2k + 3k + 4k = 1 \implies 10k = 1 \implies k = \frac{1}{10} E(X)=0110+1210+2310+3410=0+210+610+1210=2010=2E(X) = 0\cdot\frac{1}{10} + 1\cdot\frac{2}{10} + 2\cdot\frac{3}{10} + 3\cdot\frac{4}{10} = 0 + \frac{2}{10} + \frac{6}{10} + \frac{12}{10} = \frac{20}{10} = 2 E(X2)=02110+12210+22310+32410=0+210+1210+3610=5010=5E(X^2) = 0^2\cdot\frac{1}{10} + 1^2\cdot\frac{2}{10} + 2^2\cdot\frac{3}{10} + 3^2\cdot\frac{4}{10} = 0 + \frac{2}{10} + \frac{12}{10} + \frac{36}{10} = \frac{50}{10} = 5 Var(X)=E(X2)[E(X)]2=54=1\text{Var}(X) = E(X^2) - [E(X)]^2 = 5 - 4 = 1

Answer: Variance = 1


Difficulty Distribution

For JEE Main, Probability typically breaks down as:

Difficulty% of QuestionsWhat it Tests
Easy30%Classical probability, basic conditional
Medium50%Bayes, Binomial P(X = r), variance from table
Hard20%Multi-stage Bayes, combinatorial probability

In JEE Advanced, expect 1-2 questions with heavy combinatorial counting embedded inside probability. These can be Hard to Very Hard. The distribution itself (binomial, geometric) rarely shows up in Advanced — it’s more about clever sample space construction.

For Statistics specifically, JEE Main questions are almost always Easy-Medium. Mean, variance, standard deviation from a frequency table — 2 minutes if you know the formula.


Expert Strategy

Week 1 — Foundations

Start with classical probability and conditional probability. Every other concept builds on P(A|B). Do at least 20 conditional probability problems before touching Bayes — students who rush to Bayes without nailing conditional P often get confused about which direction the conditioning goes.

Week 2 — Bayes and Binomial

These two are your highest-yield topics. For Bayes: practice the “bag of balls” and “factory defects” templates until they feel mechanical. For Binomial: focus on “at least” and “at most” questions — these always require the complement method or careful summation.

Topper technique for Bayes: Always draw a quick tree diagram — Causes on the first branch, effects on the second. This makes P(AiB)P(A_i \cap B) visual. Students who skip the tree diagram make sign errors in the denominator calculation.

Week 3 — Statistics and Mixed Practice

Statistics is 1-2 hours of work. Variance formula, coefficient of variation, and mean deviation — know these cold. Then spend the rest of Week 3 on PYQs. Solve last 5 years of JEE Main papers, chapter-filtered. You’ll notice the same 4-5 templates recurring.

Time allocation in exam: Probability questions in JEE Main should take 2-3 minutes each. If you’re at 4+ minutes on a single question, mark and move — these questions reward quick pattern recognition, not grinding.

For “at least 1” problems, always use the complement: P(at least one)=1P(none)P(\text{at least one}) = 1 - P(\text{none}). This reduces a multi-term sum to a single calculation. This trick alone saves 90 seconds per question.


Common Traps

Trap 1 — Confusing “independent” with “mutually exclusive”

These are opposite ideas. Mutually exclusive means they can’t happen together: P(A∩B) = 0. Independent means knowing one doesn’t change the other: P(A∩B) = P(A)·P(B).

Two mutually exclusive events with non-zero probability are never independent. Examiners love this distinction in MCQ options.

Trap 2 — Forgetting to check if events are exhaustive in Bayes

The denominator in Bayes’ Theorem requires the events A1,A2,,AnA_1, A_2, \ldots, A_n to be mutually exclusive and exhaustive (they must partition the sample space). If they don’t add up to the full sample space, Bayes doesn’t apply directly. Always verify P(Ai)=1\sum P(A_i) = 1 before applying the formula.

Trap 3 — Wrong n in Binomial for “at least” questions

“Find P(at least 2 successes in 6 trials)” — many students write this as 1P(X=0)P(X=1)1 - P(X=0) - P(X=1) but accidentally use n=5 instead of n=6 in the (nr)\binom{n}{r} term. Slow down when writing out the formula.

Trap 4 — Variance is not E(X²)

Var(X)=E(X2)[E(X)]2\text{Var}(X) = E(X^2) - [E(X)]^2, not just E(X2)E(X^2). This is the most common arithmetic mistake in Statistics problems. Always subtract the square of the mean.

Trap 5 — Classical probability with ordered vs unordered samples

“Two balls are drawn from a bag” — are you counting ordered pairs or unordered pairs? Be consistent. If you use (n2)\binom{n}{2} for total outcomes, use (k2)\binom{k}{2} for favourable. Mixing ordered numerator with unordered denominator (or vice versa) gives the wrong answer even when your logic is right.


With 2-3 questions guaranteed in JEE Main and a clear set of repeating templates, Probability is one of the few chapters where consistent practice directly converts into marks. The students who score full marks here aren’t more talented — they’ve just seen the patterns often enough that the template recognition is automatic.