JEE Weightage:

JEE Chem — Coordination Compounds Deep Dive

JEE Chem — Coordination Compounds Deep Dive — JEE strategy, weightage, PYQs, traps

5 min read

Chapter Overview & Weightage

Coordination Compounds is one of the most heavily tested chapters in JEE Main Inorganic Chemistry — typically 2 to 3 questions per paper worth 8 to 12 marks. JEE Advanced also pulls 1 to 2 questions, often demanding deeper application of crystal field theory or isomerism.

The chapter has four big themes: nomenclature, isomerism, crystal field theory (CFT), and magnetic + colour properties.

YearJEE Main WeightageJEE Advanced
202412 marks8 marks
20238 marks4 marks
202212 marks8 marks
20218 marks4 marks
202012 marks8 marks

Key Concepts You Must Know

  • A coordination compound has a central metal ion surrounded by ligands. The metal and ligands together form the coordination sphere.
  • Coordination number is the number of ligand donor atoms attached to the metal.
  • Ligands are classified by denticity (number of binding sites): monodentate (Cl⁻, NH₃), bidentate (en, ox²⁻), polydentate (EDTA⁴⁻).
  • Isomerism: structural (linkage, ionisation, coordination, hydrate) and stereo (geometrical, optical).
  • Crystal Field Theory explains splitting of d-orbitals into t2gt_{2g} and ege_g in octahedral fields, and into ee and t2t_2 in tetrahedral.
  • Spectrochemical series ranks ligands by crystal field strength: I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < H₂O < NH₃ < en < CN⁻ < CO.

Important Concepts and Rules

Octahedral: d-orbitals split into lower t2gt_{2g} (3) and upper ege_g (2), separated by Δo\Delta_o.

Tetrahedral: ee (lower, 2) and t2t_2 (upper, 3), with Δt=49Δo\Delta_t = \frac{4}{9}\Delta_o.

For octahedral d⁴–d⁷ configurations:

  • Strong-field ligand (large Δo\Delta_o > pairing energy P): low-spin, electrons pair in t2gt_{2g}.
  • Weak-field ligand (small Δo\Delta_o < P): high-spin, electrons spread before pairing.

Tetrahedral complexes are almost always high-spin (small Δt\Delta_t).

μ=n(n+2)BM\mu = \sqrt{n(n+2)}\,\text{BM}

where nn is the number of unpaired electrons.

EAN=Zoxidation state+2×coordination number\text{EAN} = Z - \text{oxidation state} + 2 \times \text{coordination number}

Stable complexes often satisfy EAN = noble gas configuration (e.g., 36 for Kr).

Solved Previous Year Questions

PYQ 1 (JEE Main 2024, 4 marks)

Find the spin-only magnetic moment of [CoF6]3[CoF_6]^{3-}.

Solution:

Co³⁺ has electron configuration [Ar]3d6[Ar]\,3d^6. F⁻ is a weak-field ligand (low in spectrochemical series), so the complex is high-spin.

For octahedral high-spin d⁶: 4 unpaired electrons in t2g4eg2t_{2g}^4 e_g^2.

μ=4×6=244.9BM\mu = \sqrt{4 \times 6} = \sqrt{24} \approx 4.9\,\text{BM}

PYQ 2 (JEE Main 2023, 4 marks)

Number of geometrical isomers of [Co(NH3)3Cl3][Co(NH_3)_3 Cl_3] is:

Solution:

Octahedral MA3B3MA_3B_3 has two geometrical isomers: facial (fac) and meridional (mer).

In fac, the three NH₃ occupy one face. In mer, they form a meridian (great circle).

Answer: 2.

PYQ 3 (JEE Advanced 2022)

Among the following, the complex that exhibits optical isomerism is:

(a) [Pt(NH3)2Cl2][Pt(NH_3)_2 Cl_2] (square planar) (b) [Co(en)3]3+[Co(en)_3]^{3+} (octahedral) (c) [Ni(CO)4][Ni(CO)_4] (tetrahedral) (d) [Pt(NH3)4]2+[Pt(NH_3)_4]^{2+} (square planar)

Solution:

Optical isomerism requires absence of an internal mirror plane.

(a) Square planar with two pairs of identical ligands — has mirror plane. (b) Octahedral with three bidentate ligands — chiral! Two non-superimposable mirror images (Δ and Λ). (c) Tetrahedral with four identical ligands — has mirror planes. (d) Has a mirror plane.

Answer: (b) [Co(en)3]3+[Co(en)_3]^{3+}.

Difficulty Distribution

  • Easy (nomenclature, EAN, identifying ligand type): 4 marks per Main paper
  • Medium (geometric isomerism, magnetic moment, CFT splitting diagrams): 8 marks
  • Hard (optical isomerism, mixed CFT + spectrochemistry): 4 marks in Advanced

Expert Strategy

For magnetic moment questions, the workflow is fixed: 1) find oxidation state of metal, 2) find d-electron count, 3) identify field strength of ligand (strong/weak), 4) draw splitting diagram, 5) count unpaired, 6) plug into μ=n(n+2)\mu = \sqrt{n(n+2)}.

Memorise the spectrochemical series for ligands. Common strong-field: CN⁻, CO, NH₃, en. Common weak-field: F⁻, Cl⁻, Br⁻, I⁻, H₂O (borderline). H2OH_2O is the borderline case worth knowing well.

For octahedral complexes with three bidentate ligands (like [M(en)3][M(en)_3] or [M(ox)3][M(ox)_3]), automatically expect optical isomerism. This is a JEE Advanced favorite.

Common Traps

Trap 1 — Wrong oxidation state. Always start by computing the metal’s oxidation state correctly. Mistakes here cascade into wrong d-electron count, wrong magnetic moment, wrong everything.

Trap 2 — Assuming all octahedral d⁴-d⁷ are low-spin. Field strength of the ligand decides. F⁻ gives high-spin; CN⁻ gives low-spin.

Trap 3 — Confusing geometrical and optical isomerism. Cis-trans is geometrical (different connectivity in 3D). Optical isomerism requires non-superimposability with mirror image.

Trap 4 — Mis-identifying tetrahedral splitting. In tetrahedral, t2t_2 is upper and ee is lower — opposite of octahedral. Easy to swap under exam pressure.

Trap 5 — Forgetting that Δt<Δo\Delta_t < \Delta_o. Tetrahedral splitting is much smaller, so almost all tetrahedral complexes are high-spin.