s-Block Elements — Alkali and Alkaline Earth Metals

s-Block Elements — Alkali and Alkaline Earth Metals

10 min read

The Most Reactive Metals

The s-block elements — Groups 1 (alkali metals: Li, Na, K, Rb, Cs, Fr) and Group 2 (alkaline earth metals: Be, Mg, Ca, Sr, Ba, Ra) — are the most electropositive elements in the periodic table. They lose electrons easily, react vigorously with water, and form strongly basic hydroxides.

This chapter is theory and trend-based. CBSE Class 11 gives 4-5 marks. NEET asks 1-2 questions on properties, anomalous behaviour, and compounds.

graph TD
    A[s-Block Elements] --> B[Group 1: Alkali Metals]
    A --> C[Group 2: Alkaline Earth Metals]
    B --> D[Trends down the group]
    D --> D1[Atomic radius increases]
    D --> D2[IE decreases]
    D --> D3[Reactivity increases]
    D --> D4[Electronegativity decreases]
    C --> E[Trends down the group]
    E --> E1[Similar to Group 1]
    E --> E2[Higher IE than Group 1]
    E --> E3[Form M²⁺ ions]
    B --> F[Anomalous: Li]
    C --> G[Anomalous: Be]
    F --> H[Diagonal with Mg]
    G --> I[Diagonal with Al]

PropertyTrend down the group
Atomic radiusIncreases
Ionization energyDecreases
ElectronegativityDecreases
Melting pointDecreases
Reactivity with waterIncreases (Li slow, Cs explosive)
Flame colourLi-crimson, Na-yellow, K-violet, Rb-red, Cs-blue
PropertyTrend
Atomic radiusIncreases down group
IE1_1 + IE2_2Decreases down group
Reducing powerIncreases
Solubility of hydroxidesIncreases (Be(OH)2_2 insoluble, Ba(OH)2_2 soluble)
Solubility of sulphatesDecreases (MgSO4_4 soluble, BaSO4_4 insoluble)

The opposite solubility trends of hydroxides (increases) and sulphates (decreases) are a favourite NEET/board question. Memorise them as a pair.


Anomalous Behaviour

Lithium is different from other alkali metals because of its very small size and high charge density. It shows a diagonal relationship with Mg: both form covalent compounds, both react with N2_2 to form nitrides, and both carbonates decompose on heating.

Beryllium is different from other alkaline earth metals for similar reasons. Its diagonal relationship with Al: both are amphoteric, both form covalent halides, both chlorides are Lewis acids.


Important Compounds

Sodium Hydroxide (NaOH, Caustic Soda)

Manufactured by Castner-Kellner process (electrolysis of brine with Hg cathode) or membrane cell.

Sodium Carbonate (Na2_2CO3_3, Washing Soda)

Made by Solvay process. Used in glass manufacture and water softening.

Calcium Oxide (CaO, Quicklime)

CaCO3ΔCaO+CO2\text{CaCO}_3 \xrightarrow{\Delta} \text{CaO} + \text{CO}_2. Highly exothermic reaction with water.

Plaster of Paris (CaSO412_4 \cdot \frac{1}{2}H2_2O)

Made by heating gypsum (CaSO42_4 \cdot 2H2_2O) to 120°C. Sets hard when mixed with water.


Common Mistakes to Avoid

Mistake 1 — Confusing solubility trends. Hydroxides: solubility INCREASES down Group 2. Sulphates: solubility DECREASES. Many students swap these.

Mistake 2 — Forgetting anomalous properties of Li and Be. Li does NOT form superoxides (only forms Li2_2O). Be does NOT react with water. These exceptions are frequently tested.

Mistake 3 — Not knowing diagonal relationships. Li ~ Mg and Be ~ Al. Questions on these appear in both NEET and JEE.


Practice Questions

Q1. Why is Li different from other alkali metals?

Li has very small size and high charge density, leading to high polarizing power. This makes its compounds more covalent, unlike the ionic compounds of Na, K, etc. Li also doesn’t form superoxide or peroxide easily.

Q2. Arrange the hydroxides of Group 2 in order of increasing basicity.

Be(OH)2_2 (amphoteric) << Mg(OH)2_2 << Ca(OH)2_2 << Sr(OH)2_2 << Ba(OH)2_2. Basicity increases down the group.

Q3. Why does BeSO4_4 dissolve in water but BaSO4_4 does not?

Be2+^{2+} is small with high charge density — its hydration energy exceeds lattice energy, so it dissolves. Ba2+^{2+} is large with low hydration energy — lattice energy dominates, so BaSO4_4 is insoluble.

Q4. What happens when Na reacts with water?

2Na+2H2O2NaOH+H22\text{Na} + 2\text{H}_2\text{O} \to 2\text{NaOH} + \text{H}_2 \uparrow. Vigorous reaction, sodium dashes across the surface, hydrogen gas evolved.


FAQs

Why do alkali metals not occur free in nature?

They are extremely reactive — they react with oxygen, water, and most non-metals. They always exist as compounds (NaCl, KCl, etc.).

Why do alkali metals give characteristic flame colours?

Electrons are excited to higher energy levels by the flame, and when they return, they emit light of characteristic wavelengths. The low IE of alkali metals makes this excitation easy.

Why is Na2_2CO3_3 stable but Li2_2CO3_3 decomposes on heating?

Li+^+ is small with high polarizing power — it distorts the carbonate ion and promotes decomposition. Na+^+ is larger and cannot polarize as effectively, so Na2_2CO3_3 is stable.


Deeper Concepts

Oxides — what forms when you burn alkali metals

The type of oxide formed depends on the size of the cation:

MetalOxide formedReaction
LiNormal oxide (Li2_2O)4Li+O22Li2O4\text{Li} + \text{O}_2 \rightarrow 2\text{Li}_2\text{O}
NaPeroxide (Na2_2O2_2)2Na+O2Na2O22\text{Na} + \text{O}_2 \rightarrow \text{Na}_2\text{O}_2
K, Rb, CsSuperoxide (KO2_2)K+O2KO2\text{K} + \text{O}_2 \rightarrow \text{KO}_2

Why? Larger cations stabilise larger anions. The superoxide ion O2_2^- is large and needs a large cation (K+^+, Rb+^+, Cs+^+) to stabilise the crystal lattice. Li+^+ is too small to stabilise anything bigger than O2^{2-}.

“Which alkali metal does NOT form a superoxide?” is a favourite NEET/JEE MCQ. The answer is Li and Na. Li forms only the normal oxide; Na forms the peroxide.

Thermal stability of carbonates and hydroxides

Group 1 carbonates: All are thermally stable except Li2_2CO3_3. Stability increases down the group because the larger cation has lower polarising power.

Group 2 carbonates: All decompose on heating. Stability order: BeCO3_3 (least) < MgCO3_3 < CaCO3_3 < SrCO3_3 < BaCO3_3 (most). Again, larger cation = lower polarising power = higher thermal stability.

The same trend holds for hydroxides and nitrates.

High polarising power of a cation (small size, high charge) increases covalent character in the bond. Covalent compounds decompose more easily because the cation distorts the electron cloud of the anion. This is why LiCl is more covalent than NaCl, and BeCl2_2 is more covalent than MgCl2_2.

Reaction with water — the trend

Reactivity with water increases down both groups:

  • Li reacts slowly with cold water
  • Na reacts vigorously, melts into a ball
  • K catches fire (lilac flame)
  • Rb and Cs explode on contact
2M+2H2O2MOH+H22\text{M} + 2\text{H}_2\text{O} \rightarrow 2\text{MOH} + \text{H}_2 \uparrow

Group 2 metals react more slowly than their Group 1 neighbours. Be does not react with water at all. Mg reacts only with hot water or steam. Ca onwards react with cold water.

Worked Example — Predicting products

Sodium peroxide reacts with water to give NaOH and H2_2O2_2:

2Na2O2+2H2O4NaOH+O22\text{Na}_2\text{O}_2 + 2\text{H}_2\text{O} \rightarrow 4\text{NaOH} + \text{O}_2

The O2_2 released makes Na2_2O2_2 useful in submarines and spacecraft — it absorbs CO2_2 (reacts with it) and releases O2_2.

Li reacts directly with N2_2 at room temperature: 6Li+N22Li3N6\text{Li} + \text{N}_2 \rightarrow 2\text{Li}_3\text{N}. This is because Li+^+ is small enough to form a stable lattice with the small N3^{3-} ion. Na+^+ is too large — the lattice energy would be too low to make the reaction favourable. This is part of the Li-Mg diagonal relationship.

Additional Solved Examples

Example 4 (JEE Main): Arrange BeSO4_4, MgSO4_4, CaSO4_4, SrSO4_4, BaSO4_4 in decreasing order of solubility.

BeSO4>MgSO4>CaSO4>SrSO4>BaSO4\text{BeSO}_4 > \text{MgSO}_4 > \text{CaSO}_4 > \text{SrSO}_4 > \text{BaSO}_4

Sulphate solubility decreases down Group 2 because hydration energy decreases faster than lattice energy as cation size increases.

Example 5 (NEET): Dead burnt plaster is obtained by heating gypsum above 200°C. What is it?

Heating gypsum (CaSO42_4 \cdot 2H2_2O) at 120°C gives Plaster of Paris (CaSO412_4 \cdot \frac{1}{2}H2_2O). Heating above 200°C gives anhydrous CaSO4_4 — dead burnt plaster. It does not set with water because the crystal structure is destroyed. This is why temperature control matters in plaster manufacture.

Additional Practice Questions

Q5. Why is BeCl2_2 covalent while MgCl2_2 is ionic?

Be2+^{2+} is very small with high charge density (high polarising power). By Fajans’ rules, it distorts the electron cloud of Cl^- heavily, making the bond significantly covalent. Mg2+^{2+} is larger, polarises less, and forms a more ionic compound.

Q6. What is washing soda? How is it prepared commercially?

Washing soda is Na2_2CO310_3 \cdot 10H2_2O (hydrated sodium carbonate). It is prepared by the Solvay process: NaCl + NH3_3 + CO2_2 + H2_2O \rightarrow NaHCO3_3 + NH4_4Cl. The NaHCO3_3 is heated to give Na2_2CO3_3, which is then crystallised. Uses: glass manufacture, softening hard water, laundry.

Q7. Why is KO2_2 used in space capsules?

Potassium superoxide reacts with CO2_2 exhaled by astronauts to release O2_2: 4KO2+2CO22K2CO3+3O24\text{KO}_2 + 2\text{CO}_2 \rightarrow 2\text{K}_2\text{CO}_3 + 3\text{O}_2. It simultaneously removes CO2_2 and regenerates O2_2 — a dual-purpose life support chemical.

Q8. Cement is a mixture involving CaO. Name the two key compounds in Portland cement.

Tricalcium silicate (Ca3_3SiO5_5) and dicalcium silicate (Ca2_2SiO4_4). These silicates hydrate when mixed with water, forming a hard interlocking crystal structure. Tricalcium aluminate (Ca3_3Al2_2O6_6) is also present and controls the setting rate.


Exam Weightage

ExamTypical weightKey topics
CBSE Class 114–5 marksTrends, anomalous behaviour, compounds
JEE Main1–2 questionsDiagonal relationships, solubility trends
NEET1–2 questionsCompounds, properties, thermal stability

Biological importance of s-block elements

  • Na+^+ and K+^+ maintain osmotic balance and nerve impulse transmission. The Na+^+/K+^+ pump is essential for every cell.
  • Ca2+^{2+} forms bones and teeth (as hydroxyapatite), triggers muscle contraction, and is essential for blood clotting.
  • Mg2+^{2+} is at the centre of chlorophyll. Without Mg, photosynthesis stops.

Industrial applications

CompoundUse
NaOH (caustic soda)Soap making, paper, textiles
Na2_2CO3_3 (washing soda)Glass, water softening, laundry
NaHCO3_3 (baking soda)Cooking, antacid, fire extinguisher
CaO (quicklime)Cement, steel purification
Ca(OH)2_2 (slaked lime)Whitewashing, water treatment
CaSO412_4 \cdot \frac{1}{2}H2_2O (POP)Casts, moulds, construction

For board exams, learn the formula, common name, and one use for each compound. This three-column memory format covers most 2-mark questions.

FAQs

Why is sodium stored under kerosene?

Sodium reacts vigorously with moisture in air, producing NaOH and H2_2. It can catch fire. Kerosene is a non-reactive hydrocarbon that keeps sodium away from air and moisture.

Why is Be amphoteric while other Group 2 elements are basic?

Be2+^{2+} has very high charge density (small size, +2 charge), which gives BeO and Be(OH)2_2 significant covalent character. This makes them amphoteric — they react with both acids and bases. Mg onwards, the hydroxides are purely basic.

What is the Solvay process?

An industrial method to produce Na2_2CO3_3 (washing soda) from NaCl, NH3_3, and CO2_2. The intermediate NaHCO3_3 precipitates out (less soluble) and is heated to give Na2_2CO3_3. NH3_3 is recovered and recycled. The process cannot be used for K2_2CO3_3 because KHCO3_3 is too soluble to precipitate.

Practice Questions