Which of C₂H₅OH and CH₃OCH₃ are functional group isomers

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Question

Are C₂H₅OH and CH₃OCH₃ functional group isomers? Justify your answer and explain the difference in their properties.

Solution — Step by Step

C₂H₅OH (ethanol): C₂H₆O → 2 carbons, 6 hydrogens, 1 oxygen.

CH₃OCH₃ (dimethyl ether): C₂H₆O → 2 carbons, 6 hydrogens, 1 oxygen.

Both have the molecular formula C2H6O\mathbf{C_2H_6O}. ✓ This is the first requirement for any type of isomerism.

C₂H₅OH — contains the hydroxyl group (–OH) → it is an alcohol (primary alcohol, ethanol).

CH₃OCH₃ — contains the ether linkage (–O–) → it is an ether (dimethyl ether, methoxymethane).

The functional groups are different. This confirms they are functional group isomers — same molecular formula, different functional groups.

Functional group isomers (also called functional isomers): Compounds with the same molecular formula but different functional groups. They belong to different homologous series and have different physical and chemical properties.

C₂H₅OH and CH₃OCH₃ are textbook examples of this type of isomerism.

PropertyEthanol (C₂H₅OH)Dimethyl ether (CH₃OCH₃)
Boiling point78.4°C−24°C
State at room tempLiquidGas
Solubility in waterMiscible (hydrogen bonding with water)Slightly soluble
With Na metalReacts — releases H₂ gasNo reaction
With HINo reaction at room tempReacts (cleavage of ether)
IUPAC nameEthanolMethoxymethane

The dramatically different boiling points (78.4°C vs −24°C) arise because ethanol forms strong hydrogen bonds (–OH group), while ether cannot act as a hydrogen bond donor.

Why This Works

The molecular formula tells us the raw material available — 2 carbons, 6 hydrogens, 1 oxygen. The functional group tells us how those atoms are arranged relative to each other and how the compound behaves. Placing the oxygen as –OH (bonded to one carbon) versus –O– (bridging two carbons) gives completely different architectures and therefore completely different reactivity and physical properties.

This is the power of structural isomerism — same atoms, different connections, totally different substances.

CBSE Class 12 and JEE both test functional group isomerism. Common pairs to know:

  • Alcohols ↔ Ethers (CnH2n+2OC_nH_{2n+2}O)
  • Aldehydes ↔ Ketones (CnH2nOC_nH_{2n}O)
  • Carboxylic acids ↔ Esters (CnH2nO2C_nH_{2n}O_2)
  • Primary amines ↔ Secondary/tertiary amines ↔ Imines (CnH2n+3NC_nH_{2n+3}N etc.)

Alternative Method

You can verify isomerism by checking degrees of unsaturation (DoU):

  • C₂H₅OH: DoU = 0 (saturated, no rings/double bonds)
  • CH₃OCH₃: DoU = 0 (same)

Equal DoU is consistent with being isomers. Since the molecular formula and DoU match but the functional groups differ, they are functional group isomers.

Common Mistake

Students sometimes say ethanol and dimethyl ether are “metamers” (a subtype of structural isomers where the same functional group is attached to different alkyl groups). Metamerism requires the same functional group — here, one is an alcohol and the other is an ether. They are functional group isomers, not metamers. Metamers would be something like CH₃–O–CH₂CH₃ and C₂H₅–O–C₂H₅ (both ethers, different alkyl groups).

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