Polymers: PYQ Walkthrough (4)

easy 2 min read

Question

Classify the following polymers as addition or condensation, and as homopolymer or copolymer: (a) Nylon 6,6, (b) Polythene, (c) Bakelite, (d) Buna-S.

Solution — Step by Step

Made by condensation polymerisation of hexamethylenediamine and adipic acid. Two different monomers → copolymer. Water is eliminated during each linkage formation.

Type: condensation copolymer.

Made by addition polymerisation of ethene (CH2=CH2CH_2=CH_2). Single monomer → homopolymer. No small molecule eliminated.

Type: addition homopolymer.

Made by condensation of phenol and formaldehyde. Two different monomers → copolymer. Water is eliminated.

Type: condensation copolymer.

Made by addition (free-radical) copolymerisation of butadiene and styrene. Two different monomers → copolymer. No elimination.

Type: addition copolymer.

Final answers:

  • Nylon 6,6: condensation copolymer
  • Polythene: addition homopolymer
  • Bakelite: condensation copolymer
  • Buna-S: addition copolymer

Why This Works

Polymerisation type depends on monomer structure. Addition uses unsaturated monomers (C=CC=C or CCC\equiv C) — they open up and chain together with no byproduct. Condensation uses bifunctional monomers (like diols + diacids) and eliminates a small molecule (water, HCl, etc.).

Homopolymer vs copolymer is purely about the number of monomer types — one type gives a homopolymer regardless of mechanism.

Alternative Method

Use the structural approach. If the repeat unit shows an amide (CONH-CONH-) or ester (COO-COO-) linkage that wasn’t in the monomer, it’s condensation. If the repeat unit looks like the monomer minus a double bond, it’s addition.

For NEET, memorise the four classic copolymers: nylon 6,6 (condensation), Buna-N (addition), Buna-S (addition), Bakelite (condensation). The exam picks from this list.

Common Mistake

Calling nylon 6 (made from caprolactam alone) a copolymer. It’s a homopolymer because there’s only one monomer, despite being a condensation polymer. Don’t confuse the two classifications.

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