p-Block Elements: Numerical Problems Set (7)

easy 2 min read

Question

How many grams of HCl\text{HCl} are produced when 44 moles of H2\text{H}_2 reacts completely with chlorine? Reaction: H2+Cl22HCl\text{H}_2 + \text{Cl}_2 \to 2\text{HCl}.

Solution — Step by Step

From the balanced equation: 11 mole of H2_2 produces 22 moles of HCl. So 44 moles of H2_2 produces 88 moles of HCl.

Molar mass of HCl: 1+35.5=36.51 + 35.5 = 36.5 g/mol.

Mass=8×36.5=292 g\text{Mass} = 8 \times 36.5 = 292 \text{ g}

Final answer: 292292 g of HCl.

Why This Works

Stoichiometry follows directly from the balanced equation. The coefficients give the ratio of moles, not masses. Convert masses to moles, apply the ratio, convert back to masses. That’s the universal recipe.

For p-block reactions, the classic trap is unbalanced equations. Always balance first — otherwise the ratio is wrong from the start.

Alternative Method

By mass conservation: 44 moles H2_2 = 88 g; complete reaction with 44 moles Cl2_2 = 284284 g. Total mass on right: 8+284=2928 + 284 = 292 g, which equals the HCl mass. The arithmetic confirms the answer.

For NEET p-block stoichiometry, verify the equation is balanced before proceeding. Common reactions like 4NH3+5O24NO+6H2O4\text{NH}_3 + 5\text{O}_2 \to 4\text{NO} + 6\text{H}_2\text{O} have non-trivial coefficients — drill them.

Common Mistake

Students sometimes use the ratio 1:11:1 (H2_2:HCl) instead of 1:21:2, forgetting the coefficient of 22 on HCl. The mole ratio comes straight from the balanced equation — read it carefully every time, even for “simple” reactions.

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