p-Block Elements: Common Mistakes and Fixes (9)

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Question

Explain the trend in oxidation states of group 15 elements (N, P, As, Sb, Bi) and predict why BiCl5\text{BiCl}_5 does not exist while PCl5\text{PCl}_5 does.

Solution — Step by Step

Group 15 elements have valence configuration ns2np3ns^2 np^3. They can show oxidation states from 3-3 to +5+5.

Common: 3-3 (in NH3_3, PH3_3), +3+3 (in PCl3_3, BiCl3_3), +5+5 (in HNO3_3, PCl5_5).

Going down the group, the energy gap between nsns and npnp orbitals increases. The ns2ns^2 pair becomes increasingly reluctant to participate in bonding — this is the inert pair effect.

So the +3+3 oxidation state (using only np3np^3) becomes more stable down the group, while +5+5 (using both nsns and npnp) becomes less stable.

For Bi (heaviest in the group), the 6s26s^2 pair is very tightly held due to poor shielding by the filled 4f4f and 5d5d orbitals (lanthanide and dd-block contraction). Promoting electrons from 6s6s to bond is energetically unfavorable.

So Bi prefers +3+3. BiCl3\text{BiCl}_3 exists; BiCl5\text{BiCl}_5 does not (or is highly unstable).

P, much smaller, has accessible 3d3d orbitals and easier 3s3s promotion. So both PCl3_3 and PCl5_5 are stable.

+5+5 state stability: N \approx P > As > Sb > Bi.

+3+3 state stability: N < P < As < Sb < Bi.

Final answer: BiCl5\text{BiCl}_5 doesn’t exist due to the inert pair effect — Bi’s 6s26s^2 electrons are too tightly bound to participate in bonding. PCl5_5 exists because P’s 3s23s^2 is not subject to this effect.

Why This Works

The inert pair effect is one of the most important down-group trends in p-block chemistry. It shows up in:

  • Sn vs Pb: SnCl4_4 stable, PbCl4_4 less stable; PbCl2_2 more stable than SnCl2_2.
  • Tl in group 13: +1+1 favored over +3+3.
  • Bi in group 15: +3+3 favored over +5+5.

The root cause: poor shielding by filled inner orbitals (especially 4f4f in heavy elements) makes the nsns pair feel a high effective nuclear charge, lowering its energy and making it a “nuclear-bound spectator”.

Alternative Method

Argue from bond energies: the average M-Cl bond energy in BiCln_n is much lower than in PCln_n due to weaker Bi-Cl overlap (size mismatch). Five Bi-Cl bonds release less energy than the cost of promoting Bi’s 6s26s^2 pair, so the +5+5 state is thermodynamically unfavorable.

Common Mistake

Students confuse “inert pair effect” with “loss of dd-orbitals”. The inert pair effect is about the ss-orbital pair becoming reluctant to bond, not about dd-orbital availability. Both factors contribute to instability of higher oxidation states down a group, but they’re distinct phenomena.

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