Question
Arrange the following in order of increasing acidic strength of their hydrides: , , , . Justify the trend using bond strength and electronegativity arguments.
Solution — Step by Step
These are Group 16 hydrides — oxygen, sulfur, selenium, tellurium. As we go down the group, atomic size increases and bond length to hydrogen increases.
Acidity in depends on how easily can leave. Weaker bond → easier ionisation → stronger acid.
Bond enthalpies (kJ/mol): = 463, = 347, = 276, = 238. Strength decreases sharply down the group.
Electronegativity decreases down the group ( > > > ). One might expect more electronegative atoms to release more readily — but the data shows the opposite trend dominates. Bond strength wins.
values: , , , .
Why This Works
For Group 16 hydrides, the dominant factor is bond strength, not electronegativity. As bond length grows, the bond becomes weaker and the leaves more readily. This is the same trend as for HCl < HBr < HI in halogens: down the group, hydrides become stronger acids.
The “electronegativity → acidity” rule applies across a period, not down a group. CH₄ < NH₃ < H₂O < HF in acidity matches electronegativity. Down a group, bond strength dominates.
Alternative Method
Use (other terms). Since falls dramatically down the group, and the other terms (hydration, etc.) move less, falls and rises.
Common Mistake
Students apply the electronegativity rule and predict should be the strongest acid in the group. Wrong direction — water’s bond is the strongest of the four, making it the weakest acid. Always think about which factor (electronegativity vs bond strength) dominates for the specific trend asked.