Coordination Compounds: Exam-Pattern Drill (8)

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Question

(JEE Main pattern) For the complex [Co(NH3)6]3+[\text{Co(NH}_3)_6]^{3+}, find: (a) oxidation state of cobalt, (b) coordination number, (c) hybridisation of central atom, (d) magnetic behaviour, (e) IUPAC name.

Solution — Step by Step

NH₃ is neutral. Charge on complex = +3. So oxidation state of Co = +3.

Six NH₃ ligands attached, each contributing one lone pair (monodentate). Coordination number = 6.

Co³⁺ has electron configuration [Ar]3d6[\text{Ar}]3d^6. NH₃ is a strong-field ligand → causes pairing of the d electrons.

In strong field with 6 d electrons all paired in three t2gt_{2g} orbitals, the two ege_g orbitals are empty. The two empty 3d orbitals, plus 4s and three 4p, form d²sp³ hybrid orbitals (inner orbital complex).

All electrons paired → diamagnetic.

Hexa- (6 ligands) + ammine (NH₃) + cobalt + (III) for oxidation state. The complex is a cation, so we give the metal’s name first.

Hexaamminecobalt(III) ion. With chloride counterion: hexaamminecobalt(III) chloride.

Summary: (a) +3, (b) 6, (c) d²sp³, (d) diamagnetic, (e) hexaamminecobalt(III).

Why This Works

Coordination compound questions follow a fixed recipe:

  1. Charge balance → oxidation state.
  2. Count ligands → coordination number.
  3. Use the spectrochemical series to decide strong/weak field → pairing → hybridisation.
  4. Count unpaired electrons → magnetic moment μ=n(n+2)\mu = \sqrt{n(n+2)} BM.
  5. Name with prefixes (mono, di, tri, hexa) and ligand-then-metal order.

NH₃, CN⁻, CO are strong-field ligands. F⁻, Cl⁻, H₂O are weak-field. Memorize this — JEE Main asks every year.

Inner orbital complex (d²sp³) → low spin → fewer unpaired electrons → diamagnetic or weakly paramagnetic. Outer orbital complex (sp³d²) → high spin → more unpaired → strongly paramagnetic.

Alternative Method

Crystal field theory: in octahedral strong field, Δo>P\Delta_o > P (pairing energy), so d⁶ pairs in t2g6eg0t_{2g}^6 e_g^0 — low spin, diamagnetic. Same conclusion via CFT instead of VBT (valence bond theory).

Common Mistake

Students name the complex as “cobalt(III) hexaammine” — wrong order. In IUPAC nomenclature, ligands come first (alphabetical, with prefixes ignored for ordering), then metal with oxidation state. So “hexaamminecobalt(III)”, not the reverse.

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