Amines: Numerical Problems Set (1)

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Question

A primary amine of formula C4H11NC_4H_{11}N has 44 possible structural isomers. Identify them and determine which one would be most basic in aqueous solution.

Solution — Step by Step

C4H11NC_4H_{11}N has degree of unsaturation =(24+211+1)/2=0= (2 \cdot 4 + 2 - 11 + 1)/2 = 0. Saturated, no rings — so it’s an open-chain amine.

For a primary amine (RNH2R-NH_2), RR has formula C4H9C_4H_9 (butyl group). The four butyl isomers give four structural isomers.

  1. n-butylamine: CH3CH2CH2CH2NH2CH_3CH_2CH_2CH_2NH_2
  2. sec-butylamine: CH3CH2CH(NH2)CH3CH_3CH_2CH(NH_2)CH_3
  3. iso-butylamine: (CH3)2CHCH2NH2(CH_3)_2CHCH_2NH_2
  4. tert-butylamine: (CH3)3CNH2(CH_3)_3CNH_2

Basicity in aqueous solution depends on:

(a) Inductive effect (+I groups donate, increasing electron density on N → more basic). (b) Solvation of the conjugate acid (RNH3+R-NH_3^+). Smaller, less hindered cations solvate better, stabilising them, increasing KbK_b. (c) Steric hindrance around N (larger groups can shield the lone pair).

For primary aliphatic amines, the inductive and steric effects largely cancel. In aqueous solution, n-butylamine (least branched, most easily solvated conjugate acid) is typically slightly more basic than the more branched isomers.

But the differences are small (pKb3.3pK_b \approx 3.3 to 3.63.6 for all four). Among them:

  • n-butylamine: pKb3.39pK_b \approx 3.39 (most basic)
  • sec-butylamine: pKb3.40pK_b \approx 3.40
  • iso-butylamine: pKb3.51pK_b \approx 3.51
  • tert-butylamine: pKb3.55pK_b \approx 3.55 (least basic of these)

Final answer: n-butylamine is the most basic in aqueous solution among the four primary C4H11NC_4H_{11}N isomers.

Why This Works

In gas phase, basicity follows pure inductive donation: 3° > 2° > 1° amines. But in aqueous solution, the order shuffles because:

  • RNH3+R-NH_3^+ ions need to be solvated (stabilised) by water via H-bonds.
  • More RR groups around NN = fewer HH atoms on N+N^+ available for H-bonding to water = less solvation = less stabilisation of the cation = lower KbK_b.

Net result for aqueous solution: 2° ≥ 1° > 3° for aliphatic amines. Among 1° amines specifically, less branched is slightly more basic.

Gas phase (intrinsic): 3° > 2° > 1° > NH3_3

Aqueous solution: 2° > 1° ≈ 3° > NH3_3 (anomalous order due to solvation)

Alternative Method

For exam shortcuts, just memorise that for C4H11NC_4H_{11}N primary amines, n-butylamine is the most basic in water. JEE rarely asks about the four C4 amines specifically; usually it tests the more broadly applicable rule (1° vs 2° vs 3° comparison).

When comparing 1° vs 2° vs 3° aliphatic amines in aqueous solution, remember the anomalous order: 2° is the most basic, not 3°. JEE Main 2024 had this directly.

Common Mistake

Students apply the “more alkyl = more basic” rule blindly and conclude tert-butylamine is most basic. Wrong — that’s the gas-phase order. In water, the trend reverses for tertiary amines because of poor solvation of bulky R3NH+R_3NH^+.

Another common trap: confusing basicity with nucleophilicity. They often correlate, but not always — for example, in steric situations, a less basic amine can be a better nucleophile if it’s less hindered.

A third trap: forgetting that aniline (C6H5NH2C_6H_5NH_2) is much less basic than aliphatic amines (about 10610^6 times less), because the lone pair on N is delocalised into the ring. Don’t compare aliphatic and aromatic amines using the same rules.

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