A Gas Occupies 2 L at 300 K — Volume at 600 K (Constant Pressure)?

easy CBSE JEE-MAIN NCERT Class 11 Chapter 5 3 min read

Question

A gas occupies 2 L at 300 K. If pressure is kept constant, what volume will it occupy at 600 K?


Solution — Step by Step

Pressure is constant throughout — this is the key condition that tells us Charles’ Law applies. We have initial volume V1=2 LV_1 = 2\text{ L}, initial temperature T1=300 KT_1 = 300\text{ K}, and final temperature T2=600 KT_2 = 600\text{ K}.

At constant pressure, volume is directly proportional to absolute temperature:

V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}

The ratio V/TV/T stays constant. This is Charles’ Law.

Multiply both sides by T2T_2:

V2=V1×T2T1V_2 = V_1 \times \frac{T_2}{T_1} V2=2×600300=2×2=4 LV_2 = 2 \times \frac{600}{300} = 2 \times 2 = \mathbf{4\text{ L}}

Final Answer: V₂ = 4 L


Why This Works

Charles’ Law captures a simple physical reality: when you heat a gas at constant pressure, the gas molecules move faster and need more space to maintain the same pressure against the container walls. Volume and temperature rise together in a direct proportion.

The catch — and this trips up a lot of students — is that this proportionality only holds with Kelvin temperatures, not Celsius. Kelvin is the absolute scale, so 0 K is true zero molecular motion. Celsius doesn’t have that property.

Here, the temperature doubled (300 K → 600 K), so the volume doubled (2 L → 4 L). Clean ratio, clean answer. This type of calculation is a staple of CBSE Class 11 Chapter 5 numericals.


Alternative Method

We can use the proportionality directly without the full formula. Since VTV \propto T at constant pressure:

V2V1=T2T1=600300=2\frac{V_2}{V_1} = \frac{T_2}{T_1} = \frac{600}{300} = 2

So V2=2×V1=2×2=4 LV_2 = 2 \times V_1 = 2 \times 2 = \mathbf{4\text{ L}}.

When T2T_2 is a simple multiple of T1T_1, just use the ratio directly. No need to plug into the full formula. Here, temperature doubled → volume doubled. These “clean ratio” questions are very common in board exams and JEE Main.


Common Mistake

Using Celsius instead of Kelvin. If a student accidentally writes T1=27°CT_1 = 27°C and T2=327°CT_2 = 327°C (which is how the question sometimes appears), the ratio 327/2712.1327/27 ≈ 12.1 gives a nonsense answer. Always convert to Kelvin first: T(K)=T(°C)+273T(K) = T(°C) + 273. Charles’ Law breaks with Celsius — the direct proportionality only holds on the absolute scale.

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