CBSE Weightage:

CBSE Class 7 Maths — Algebraic Expressions

CBSE Class 7 Maths — Algebraic Expressions — chapter overview, key concepts, solved examples, and exam strategy.

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Chapter Overview & Weightage

Algebraic Expressions in Class 7 is one of the most important chapters — it builds the foundation for all algebra in Class 8, 9, 10, and beyond. Students who struggle with algebraic manipulation in Class 9 often trace the problem back to shaky foundations from this chapter.

In CBSE Class 7 exams, this chapter typically carries:

Exam ComponentMarks
Very Short Answer (1 mark each)2–3 marks
Short Answer (2–3 marks each)6–8 marks
Long Answer (4–5 marks)4–5 marks
Total~15 marks

This chapter has steady marks every year. Addition/subtraction of expressions, finding values by substitution, and identifying “like terms” are the most frequently tested skills.

Key Concepts You Must Know

Variable: A letter that represents an unknown or changing quantity. Example: xx, yy, aa.

Constant: A fixed numerical value. Example: 3, −5, π\pi.

Algebraic expression: A combination of variables and constants connected by operations (+, −, ×, ÷). Example: 3x+5y23x + 5y - 2.

Term: Each part of an expression separated by + or −. Example: in 3x+5y23x + 5y - 2, the terms are 3x3x, 5y5y, and 2-2.

Coefficient: The numerical part of a term. In 3x3x, the coefficient of xx is 3. In 5y2-5y^2, the coefficient of y2y^2 is 5-5.

Like terms: Terms with the same variable(s) raised to the same power. Example: 3x3x and 7x-7x are like terms; 3x3x and 3x23x^2 are NOT.

Unlike terms: Terms with different variables or different powers.

Monomial: Expression with exactly one term (e.g., 5x25x^2). Binomial: Two terms (e.g., 3x+43x + 4). Trinomial: Three terms (e.g., x2+2x+1x^2 + 2x + 1). Polynomial: One or more terms.

Important Formulas

Rule: Only like terms can be added or subtracted. Collect like terms together, then add/subtract their coefficients.

Example: (3x+5y)+(2x3y)(3x + 5y) + (2x - 3y) = (3x+2x)+(5y3y)(3x + 2x) + (5y - 3y) = 5x+2y5x + 2y

For subtraction, change the sign of every term in the expression being subtracted, then add.

(5x+3)(2x7)=5x+32x+7=3x+10(5x + 3) - (2x - 7) = 5x + 3 - 2x + 7 = 3x + 10

Replace every variable with its given numerical value, then compute.

Example: Find 3x22x+53x^2 - 2x + 5 when x=2x = 2: =3(2)22(2)+5=3(4)4+5=124+5=13= 3(2)^2 - 2(2) + 5 = 3(4) - 4 + 5 = 12 - 4 + 5 = 13

Solved Previous Year Questions

PYQ 1 — Like and Unlike Terms (CBSE SA1 type)

Q: Identify like terms in: 3x3x, 4y4y, 5x-5x, 2xy2xy, 7y7y, 3xy-3xy.

Solution:

Like terms share the same variable:

  • Like terms with xx: 3x3x and 5x-5x
  • Like terms with yy: 4y4y and 7y7y
  • Like terms with xyxy: 2xy2xy and 3xy-3xy

Simplified: 2x+11yxy-2x + 11y - xy.

PYQ 2 — Addition of Expressions (SA1)

Q: Add 3x2+5x43x^2 + 5x - 4 and 2x23x+7-2x^2 - 3x + 7.

Solution:

Arrange like terms in columns:

  3x² + 5x - 4
+ (-2x² - 3x + 7)
─────────────────
  x²  + 2x + 3

Answer: x2+2x+3x^2 + 2x + 3

PYQ 3 — Subtraction (SA2 type)

Q: Subtract 2a+3b4c2a + 3b - 4c from 5a2b+6c5a - 2b + 6c.

Solution:

“Subtract A from B” means “B − A.” So:

(5a2b+6c)(2a+3b4c)(5a - 2b + 6c) - (2a + 3b - 4c)

Change signs of second expression: =5a2b+6c2a3b+4c= 5a - 2b + 6c - 2a - 3b + 4c

Collect like terms: =(5a2a)+(2b3b)+(6c+4c)=3a5b+10c= (5a - 2a) + (-2b - 3b) + (6c + 4c) = 3a - 5b + 10c

PYQ 4 — Value of Expression (2–3 mark)

Q: Find the value of 4p23p+54p^2 - 3p + 5 when p=2p = -2.

Solution:

=4(2)23(2)+5= 4(-2)^2 - 3(-2) + 5 =4(4)+6+5= 4(4) + 6 + 5 =16+6+5=27= 16 + 6 + 5 = 27

Watch the sign: (2)2=+4(-2)^2 = +4 and 3×(2)=+6-3 \times (-2) = +6.

Difficulty Distribution

LevelPercentageQuestion Types
Easy40%Identify terms/coefficients, simple addition of monomials
Medium45%Subtract expressions, find value by substitution
Hard15%Multi-step problems, forming expressions from word problems

The “hard” questions in this chapter are almost always word problems: “The length of a rectangle is 2x+32x + 3 and width is x1x - 1. Find the perimeter.” The maths is straightforward — the challenge is translating words into algebra. Practice 5–10 word problems before the exam.

Expert Strategy

Step 1: Make sure you can instantly recognise like terms. Write a set of 10 terms and practice grouping them in 30 seconds.

Step 2: For subtraction, ALWAYS change the sign of every term in the bracket being subtracted, then add. Write this as an explicit step — students who do it in their head make sign errors.

Step 3: For substitution, substitute the value with brackets around it — especially for negative numbers. Write (2)(-2) not just 2-2 when substituting.

In the exam: Show all steps. Even if you can do simple addition mentally, write the “collecting like terms” step. Examiners award process marks.

CBSE Class 7 exams often ask students to “add” or “subtract” two expressions — the answer must be in simplest form (like terms collected). An unsimplified answer like "3x+2x+4y3x + 2x + 4y" will lose half marks even if no arithmetic was wrong. Always simplify to ”5x+4y5x + 4y.”

Common Traps

Trap 1: Sign errors in subtraction. When subtracting (2x5)(2x - 5), every term changes sign: it becomes 2x+5-2x + 5. Students often change only the first sign and write 2x5-2x - 5. Bracket and sign it explicitly every time.

Trap 2: Treating 3x3x and 3x23x^2 as like terms. They are NOT — the powers are different. Only combine terms with identical variable-power combinations.

Trap 3: Adding coefficients when no operation is shown. 3x×4x=12x23x \times 4x = 12x^2 (multiply both coefficients AND add exponents). 3x+4x=7x3x + 4x = 7x (only add coefficients). Mixing these rules is extremely common.

Trap 4: Forgetting that a term can be a constant (number without any variable). In 3x+5y73x + 5y - 7, the constant term is 7-7. It can only be combined with other constants.