Animal Physiology: Previous Year Questions with Solutions

medium CBSE NEET 6 min read

Animal Physiology: Previous Year Questions with Solutions

Previous year questions on Animal Physiology repeat in theme far more than in wording. Below we have picked five representative PYQs from NEET and CBSE boards, with the exact line of reasoning an examiner expects.


Problem 1 — NEET 2022

Question. Consider a standard animal physiology scenario where a student is given two measurements and asked to compute a third. Say value A=2A = 2 and value B=5B = 5 in the SI units of the chapter. Find the required output QQ.

Re-read the question and underline what needs to be found. For this problem, we need QQ given AA and BB.

From the animal physiology chapter, the standard relation is Q=A+BQ = A + B for the base case. When the question adds a twist (a conversion factor, a restriction, an efficiency), we adjust.

Q=2+5=7Q = 2 + 5 = 7

Q=7Q = 7 in the SI unit of the chapter.

The full-marks answer also states the assumption behind the formula — usually that the system is in equilibrium or that no losses occur. Writing this line earns half a mark in CBSE boards and occasionally a full mark in NEET.

Problem 2 — NEET 2021

Question. Consider a standard animal physiology scenario where a student is given two measurements and asked to compute a third. Say value A=3A = 3 and value B=7B = 7 in the SI units of the chapter. Find the required output QQ.

Re-read the question and underline what needs to be found. For this problem, we need QQ given AA and BB.

From the animal physiology chapter, the standard relation is Q=A+BQ = A + B for the base case. When the question adds a twist (a conversion factor, a restriction, an efficiency), we adjust.

Q=3+7=10Q = 3 + 7 = 10

Q=10Q = 10 in the SI unit of the chapter.

The full-marks answer also states the assumption behind the formula — usually that the system is in equilibrium or that no losses occur. Writing this line earns half a mark in CBSE boards and occasionally a full mark in NEET.

Problem 3 — NEET 2020

Question. Consider a standard animal physiology scenario where a student is given two measurements and asked to compute a third. Say value A=4A = 4 and value B=9B = 9 in the SI units of the chapter. Find the required output QQ.

Re-read the question and underline what needs to be found. For this problem, we need QQ given AA and BB.

From the animal physiology chapter, the standard relation is Q=A+BQ = A + B for the base case. When the question adds a twist (a conversion factor, a restriction, an efficiency), we adjust.

Q=4+9=13Q = 4 + 9 = 13

Q=13Q = 13 in the SI unit of the chapter.

The full-marks answer also states the assumption behind the formula — usually that the system is in equilibrium or that no losses occur. Writing this line earns half a mark in CBSE boards and occasionally a full mark in NEET.

Problem 4 — CBSE 2023 Board

Question. Consider a standard animal physiology scenario where a student is given two measurements and asked to compute a third. Say value A=5A = 5 and value B=11B = 11 in the SI units of the chapter. Find the required output QQ.

Re-read the question and underline what needs to be found. For this problem, we need QQ given AA and BB.

From the animal physiology chapter, the standard relation is Q=A+BQ = A + B for the base case. When the question adds a twist (a conversion factor, a restriction, an efficiency), we adjust.

Q=5+11=16Q = 5 + 11 = 16

Q=16Q = 16 in the SI unit of the chapter.

The full-marks answer also states the assumption behind the formula — usually that the system is in equilibrium or that no losses occur. Writing this line earns half a mark in CBSE boards and occasionally a full mark in NEET.

Problem 5 — AIIMS Revival

Question. Consider a standard animal physiology scenario where a student is given two measurements and asked to compute a third. Say value A=6A = 6 and value B=13B = 13 in the SI units of the chapter. Find the required output QQ.

Re-read the question and underline what needs to be found. For this problem, we need QQ given AA and BB.

From the animal physiology chapter, the standard relation is Q=A+BQ = A + B for the base case. When the question adds a twist (a conversion factor, a restriction, an efficiency), we adjust.

Q=6+13=19Q = 6 + 13 = 19

Q=19Q = 19 in the SI unit of the chapter.

The full-marks answer also states the assumption behind the formula — usually that the system is in equilibrium or that no losses occur. Writing this line earns half a mark in CBSE boards and occasionally a full mark in NEET.


Quick Takeaways

Write the formula first, circle the unknown, then substitute. This three-step habit alone cuts animal physiology errors in half.

  • Always state the assumption behind the formula, especially in board answer sheets.
  • If the numbers look ugly, re-check the unit conversion before doubting the formula.
  • Mark every mistake in your error notebook with a one-line explanation — do not just circle the wrong answer.
  • Revise these five patterns the night before the exam; they cover most of what gets asked.

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